2
\$\begingroup\$

I have designed a PCB that I need to work in which a microcontroller drives a 24 V brushed motor. The input power to the board is 24 V, this is then lowered to 5 V by a step down converter, and this 5 V is then made "isolated" by an NTE0505. The isolated 5 V is used to power the microcontroller, RS485 communication and motor current sensing, while the 24 V and 5 V (not isolated) are used for the motor and its driver.

The PCB has 6 layers, all separated by dielectric, which are:

  1. Top layer
  2. Ground Plane
  3. Signal layer 1
  4. Signal layer 2
  5. Power Plane
  6. Bottom layer

On the fifth layer (power plane) the non-isolated and isolated 5 V are routed, suitably separated from each other by planes that do not touch.

The second layer (ground plane) is a single layer on which only the ground vias of the isolated 5 V are routed.

The 24 V ground (defined as POWER GROUND) is positioned on the top layer and bottom layer, carried on the two layers with vias that cross all the layers (as well as the 24 V). The ground of the 5 V (not isolated) is the same as the 24 V and is also routed to the two outer layers.

My doubt is mainly related to the fact that there are two grounds, that of the 24 V and 5 V non-isolated (POWER GROUND) and that of the 5 V non-isolated: does it make sense not to have at least a portion of the ground plane for the POWER GROUND? What are the best techniques for the correct use of the ground plane in the case of having two supplies isolated from each other?

The vias used cross all 6 layers of the PCB from top to bottom layer, and only the designated vias "touch" the relative planes they are connected to.

Unfortunately for copyright reasons I cannot share schematics or PCBs.

This is the actual layer stack of the PCB:

enter image description here

As you can see, there is only one type of vias which is used to cross all layers and which, depending on the connections, contacts the relevant layer for which it is used. The Ground Plane (GND) shown in the second layer refers to the ground of the isolated 5 V. My idea was to split this ground plane and also use it for the POWER GROUND used in the top layer and bottom layer as polygon pour, adding or replacing more vias like these below:

enter image description here

Does it make sense to split up the ground plane (so far only used for "isolated" ground) and use it for POWER GROUND as well?

\$\endgroup\$
5
  • \$\begingroup\$ Hi Alinik, what exactly is your question? Proper ground plane usage, best practices? Please click the edit link below your text to clarify. It'll be challenging to provide an accurate assessment from generalizations. \$\endgroup\$
    – rdtsc
    Feb 22, 2022 at 13:03
  • \$\begingroup\$ Hi @rdtsc, thank you, I have changed the text and (I hope) rewritten the question better. However, my question is about proper ground plane usage if you have two separate power supplies as in my case. \$\endgroup\$
    – Alinik
    Feb 22, 2022 at 13:49
  • 2
    \$\begingroup\$ Have you sketched how the currents flow, from the supply node out to the loads & back again? That would be my starting point. \$\endgroup\$
    – SteveSh
    Feb 22, 2022 at 13:51
  • \$\begingroup\$ @SteveSh thank you for the answer. The diagram has many components and is a bit complex, it would be very interesting however to understand how the current flows in the circuit, do you have any suggestions on how to do this analysis? I don't know if there is any simulation tool on Altium Designer. \$\endgroup\$
    – Alinik
    Feb 23, 2022 at 8:31
  • \$\begingroup\$ Remember that two conductive but isolated components on different potentials will introduce an e-field which may degrade your design in sense of EMI. Also think of common mode voltage limits of current sense device and com tranceiver. Add at least a soft reference between different grounds like Paul M suggested. If you go for a non isolated design make sure the return path for high currents are not introducing ground shifts seen by µC etc. \$\endgroup\$
    – Jogitech
    Feb 23, 2022 at 10:27

2 Answers 2

1
\$\begingroup\$

For your question there is no general answer. Although I am trying to give some advises. But first some comment on your design.

What are the best techniques for the correct use of the ground plane in the case of having two supplies isolated from each other?

This is in general i difficult question. Keep in Mind that two floating potentials can drift apart. So it is always smart to have certain defined resistance between them. Better try to avoid that and use a common ground.

There are several thinks to keep in mind.

  1. Uniform layer distribution on the surface: try to enforce that that on every place of your PCB the amount of copper layers is approx. equal. Otherwise it could happen that one side is thicker than the other which might cause issues during the production

  2. Symmetry of the full plated layers: try to distribute the full plated layers with a lot of copper symmetrically across the y-axis. This will prevent your PCB from deformation.

  3. Current Flow: As @SteveSh stated try to image how the currents are flowing back to your supply. IS there any interruption of the ground plane between this paths?

  4. EMI: IF there is a switched power supply with high voltage it is sometimes smart to keep out all ground planes underneath the transformer

  5. Defined Impedance If you need defined impedance for certain tracks like LVDS, it is always good to have a ground plane nearby.

\$\endgroup\$
0
\$\begingroup\$

Generally, isolated sections are isolated on all layers. The point of isolation is to maximize impedance between sections, and leaving overlap would increase capacitance.

Sometimes, a controlled impedance between grounds is desired anyway, to control EMI. In that case, avoiding overlap is probably still desirable to avoid crosstalk between sections of the two circuits: usually just ground-to-ground impedance is desired, if any at all.

Aside, it doesn't sound like anything about such a project demands 6 layers, maybe not even 4. But maybe that's still needed for current capacity or thermal dissipation, no idea.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.