1
\$\begingroup\$

I have a LED panel controller that can daisy chain with an another led panel controllers using a RJ14 cable to adjust a PWM that dims the panel. This is what I see on the RJ14 pins. A periodic signal that looks like this: enter image description here

Seems to go at 25 MHz or even higher.

Is this a standard protocol, or is it a proprietary thing that needs to be reverse engineered?

By the way, this is the outputted signal when the dimmer is at around 75%

Here you can see the controller with the dimmer on it outputs a PWM to two LED drivers. The ch1 connector is to receive data from a master controller and the ch2 connector is to send data to a slave one. I assume that the two channels on each connectors are outputting the same data to replicate the same PWM on both drivers. enter image description here

I will try to get more and better logic analyzer screenshots!

\$\endgroup\$
12
  • 2
    \$\begingroup\$ RJ11 is a connector style, there are a lot of different "protocols" that can use that connector. \$\endgroup\$
    – Ron Beyer
    Feb 23 at 1:21
  • \$\begingroup\$ I am already aware of that. I am trying to identify the protocol on this specific device using a RJ11. \$\endgroup\$
    – ESD
    Feb 23 at 1:23
  • 3
    \$\begingroup\$ I think the point of @RonBeyer's comment is that perhaps you could have chosen a more appropriate title for your question, since the type of connector is not relevant. \$\endgroup\$ Feb 23 at 1:26
  • \$\begingroup\$ I believe that when rj11 is used on phone lines, there are 2 pairs of signals. Since we seem to see 2 pairs of signal on the logic analyzer, I though it would help to mention it. \$\endgroup\$
    – ESD
    Feb 23 at 1:44
  • 1
    \$\begingroup\$ My mistake, I have a RJ14 cable, not a RJ11. The RJ14 has two pair for two potential telephone lines \$\endgroup\$
    – ESD
    Feb 23 at 2:27

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.