I'm a bit at a loss when trying to optimize a DC-DC converter (Half Bridge) and selecting my MOSFETs. Up to 200V I get good results (MOSFET switching times are fast ~ 20ns and the anti-parallel diode is really fast as well - Qrr is less than 1 uC). For higher voltages the MOSFET may still switch really fast ~ 20ns, even though the anti-parallel diode is bad: Qrr in the order of 20uC or even more. This causes very high switching losses at say 20kHz (well - at any frequency - but at around that frequency they become important when compared to conduction losses).

Now for the question: at high(er) voltage(s) the anti-parallel diode is bad in switching (Qrr high), even though its forward voltage drop is usually quite good (less than 1V sometimes). I don't really care since I want to use a synchronous converter (using one MOSFET in reverse conduction mode). Should I put a fast (with low Qrr ~ 0.3 nC, but with a higher forward voltage drop) diode in parallel to the MOSFET, what would happen? Would the integrated body diode still switch on because of lower V_F (even though this would happen after the fast diode switched on) or could I take advantage of the additional diode's switching speed and short-circuit it with the MOSFET just a few ns after before the body diode could turn on?

Basically: would the slow (but with "good" conducting properties: V_F low) body diode of the MOSFET still turn on even though a fast (but with "bad" conducting properties: V_F higher for the same current) diode is in parallel to it?

I hope my question was clear. Feel free to ask other details if you need them. Please link / cite any useful documentation if possible.

Additional thoughts: since the body diode may start switching (anyway) when the external diode is already conducting (having therefore a voltage drop lower than say 2V), the body diode would cause very low energy losses because the blocking voltage for it is now 2V, not the (say) 200V when the external diode was blocked. The additional switching losses caused by the unwanted turn-on of the body diode may be nothing worth to be considered. Right?

  • \$\begingroup\$ Are you driving the gate of the reverse conduction mosfet? Seems to me (but I don't know, hence the +1 on the question) the body diode would be shorted by the turned on mosfet. \$\endgroup\$ Mar 16, 2013 at 20:39
  • \$\begingroup\$ Yes, I'm driving the reverse conducting MOSFET (otherwise it wouldn't be on). My question was if the body diode could switch on AFTER the good external diode switched on and BEFORE the MOSFET would start reverse conducting (and shorting therefore both diodes). If the body diode switches on anyway, adding an external diode would only increase the switching losses of the overall converter instead of reducing them. My doubt arises from the opposed Q_rr and V_F in the good diode (Q_rr low, V_F high) and the bad diode (Q_rr high, V_F low). If the body diode had a low V_F I wouldn't have any doubt. \$\endgroup\$
    – user51166
    Mar 16, 2013 at 20:46
  • \$\begingroup\$ Would it be possible for you to give a link to the mosfet? \$\endgroup\$
    – Andy aka
    Mar 16, 2013 at 21:05
  • \$\begingroup\$ @Andyaka: I'm not sure yet (but they're all more or less equal in that respect): infineon.com/dgdl/… (Infineon IPW65R037C6 -> Qrr ~ 36uC). I compared it against a lower voltage MOSFET (for instance Infineon IPP110N20N3G infineon.com/dgdl/… -> Qrr ~ 0.64 uC). That is 20x diode switching losses. Low Qrr diode may be NXP BYC30X-600P. \$\endgroup\$
    – user51166
    Mar 16, 2013 at 21:18
  • \$\begingroup\$ @user51166 - have you looked at this device infineon.com/dgdl/… \$\endgroup\$
    – Andy aka
    Mar 16, 2013 at 22:05

1 Answer 1


After discussing this at university here's the answer: no, it's not possible.

Because if the external diode has a higher V_F value, it will be short-circuited by the low-V_F high-Q_rr internal body diode of the MOSFET. Therefore at turn of the internal body diode will have the same switching losses, since the external diode practically never goes in conduction mode.

The only "solution" seems to be to get a hand of a bit higher (~10-20%) R_DS,on MOSFET which has a better diode (10-20 times lower Q_rr) and eventually put some more MOSFETs in parallel in order to lower conduction losses.

  • \$\begingroup\$ Did you test this with a circuit in the lab? \$\endgroup\$
    – rdivilbiss
    Apr 2, 2013 at 1:08

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