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(Forgive me if I make a few mistakes in the text. My knowledge of the English language is poor.) I started learning how transistors work and I've got a question. Does the supply voltage affect the collector current? Since we have a resistor in the collector circuit, we should have a current in a collector circuit. I know that books say that base current affects collector current, but I haven't seen any of them mention the effect of supply voltage on it.
Edit: I guess I should specify that I'm talking about common emitter amplifier

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    \$\begingroup\$ It depends on the circuit the transistor is part of. You need to ask about a specific example. \$\endgroup\$
    – Finbarr
    Commented Apr 2, 2022 at 10:55
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    \$\begingroup\$ The base current does not "affect" the collector current Ic. It is the base-emitter voltage which affects the current Ic. As long as the collector voltage is large enough (some volts) not to open the base-collector pn junction, the supply voltage has only a minor influence on the current Ic (Early effect). \$\endgroup\$
    – LvW
    Commented Apr 2, 2022 at 11:24
  • \$\begingroup\$ Magnum, @LvW writes well about the topic. Careful thought regarding what he writes will advance your understanding. Worth the time. The base current is a recombination current that is required in order to keep the BJT operating when in active mode. It happens that this ratio, collector to base current, remains somewhat constant over several orders of magnitude range of currents -- for a specific BJT device. But any two devices may have quite a variance in this ratio, between them. So its specific value cannot be relied upon (its constancy can often be, but that doesn't help much in design.) \$\endgroup\$
    – jonk
    Commented Apr 2, 2022 at 18:54

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If base current \$I_B\$ is held constant, then collector current \$I_C\$ will obey this relationship:

$$ I_C = \beta I_B $$

\$\beta\$ is the transistor's DC current gain. This will be approximately true regardless of conditions at the collector. In the circuit below I keep \$I_B\$ constant at 1mA, and I vary the supply voltage \$V_S\$:

schematic

simulate this circuit – Schematic created using CircuitLab

This is a plot of collector current \$I_C\$ as I sweep supply voltage \$V_S\$ from 4V to 16V:

enter image description here

As you can see, \$I_C\$ remains fairly constant at 150mA throughout, indicating that this transistor has current gain \$\beta=150\$. There is some variation of \$\beta\$ as the potential difference \$V_{CE}\$ between collector and emitter changes, but it is mostly assumed to remain constant.

This invariance of \$I_C\$ will not be true if changing supply voltage causes a change in base current. If, for instance, I use a resistance to provide base current from the supply (in contrast to the 1mA constant current source I1 above), this will obviously make \$I_B\$ highly dependent on the supply:

schematic

simulate this circuit

Clearly \$I_B\$ here will increase as supply voltage \$V_S\$ increases, and we will see a commensurate change in collector current \$I_C\$, plotted here against \$V_S\$:

enter image description here

However, this varying \$I_C\$ is a consequence of changing \$I_B\$, and is only illustrating how you should be careful when you use phrases like "varying supply voltage". Are you really referring to "supply voltage", or do you mean conditions at the collector (\$V_{CE}\$) alone?

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Google pictures of curve tracer output for a transistor. Note that Vce tends to be on axis X, and the resulting Ic on axis Y. The diagram typically shows several traces, at specific levels of base current Ib.

There's a simple transistor-based circuit that strives specifically to have the collector current independent of collector voltage - it's called the constant current source, and it's a crucial building block of modern linear analog electronics and integrated circuits. As a further reading, even just to take a glimpse ahead if you're a novice, I'd suggest a free book called Designing analog chips by Hans Camenzind.

I agree with the others - supply voltage is a parameter of the whole circuit topology, not just the sole transistor. So I do not mean to put Vce equal to supply voltage - they may be two different things.

One tangential note: as a general rule, increasing the supply voltage of a circuit tends to make it work faster. Logic achieves faster switching, analog amps get a higher slew rate and broader bandwidth. An analog amp that's borderline unstable may be convergent below a certain level of power supply voltage, but may oscillate at higher power supply voltages.

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This question is conceptual, and to answer it, you do not need to know the internals of the transistor, but rather its behavior.

In the common-emitter amplifier stage, think of the transistor collector-emitter part as a "dynamic resistor" with varying static resistance Rce = Vce/Ic. A collector resistor with constant resistance Rc is connected in series to the "dynamic resistor" Rce. So the collector current is determined by the supply voltage Vcc and the total resistance Rtot = Rc + Rce, at first glance, according to Ohm's law - Ic = Vcc/Rtot.

If Rce was an ordinary static resistance, when Vcc increases, the current will also increase according to Ohm's law. But here Rce does not stay constant, and also increases so that to keep a constant ratio Vcc/Rtot = Ic.

So the transistor acts as a current stabilizer with adjustable resistance, and (ideally) the supply voltage does not affect the collector current.

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