What happens if we give a negative trigger pulse before a monostable multivibrator reaches it's stable state

Question

Monostable Multivibrator using Op Amp, from this link,

Obviously there is a certain amount of time that the capacitor takes to charge again from -Vcc*β to VD (0.7v) and therefore during this period a second negative pulse may not start a new timing period.

Wouldn't a negative pulse force the op-amp into negative saturation, since at any point the voltage would be less than VD(0.7), thus starting a new time period

Answer 1

Here is an example of an opamp monostable, driven by two pulses.

What one can see is that, after the "calibrated" pulse (on Vo), the capacitor must recover some voltage between the pointed tags (335-189) us.

If the time between input pulses is changed, then the width of the "timing pulse" can change or is something "random".