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Monostable Multivibrator using Op Amp, from this link,

enter image description here

Obviously there is a certain amount of time that the capacitor takes to charge again from -Vcc*β to VD (0.7v) and therefore during this period a second negative pulse may not start a new timing period.

Wouldn't a negative pulse force the op-amp into negative saturation, since at any point the voltage would be less than VD(0.7), thus starting a new time period

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  • \$\begingroup\$ Please include the schematic of the circuit in your question. External links might not work in a few months or years. \$\endgroup\$
    – The Photon
    Apr 21, 2022 at 14:20

1 Answer 1

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Here is an example of an opamp monostable, driven by two pulses.

enter image description here

What one can see is that, after the "calibrated" pulse (on Vo), the capacitor must recover some voltage between the pointed tags (335-189) us.

If the time between input pulses is changed, then the width of the "timing pulse" can change or is something "random".

enter image description here

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