This is a picture of a homework question that I do not understand all too well. The question is below: The power supply in Fig. P9.59 generates 50 kW the line impedance is 0.095 . If the load consumes 43 kW and the voltmeter leads 220 V rms, determine the ammeter leading and the power factor of the inductive load.
I don't know how to start. I know some functions that are most likely to be used: P = Vrms x Irms x cos(theta) with cos(theta) being the power factor. Also, I extracted the information and I don't understand how to find the current. That being the obvious first step. I tried using P = VI => 7kW / 220 = I. But, I checked the answer my professor put online and it's not the same. He somehow got Irms = 271.4 Arms. I don't understand it. please help. Thanks.