0
\$\begingroup\$

I have incomplete details of a very interesting RCCR oscillator circuit that, back in 1960, used just 3 transistors as the amplifier. In those days, the transistors were germanium PNP, almost certainly. I cannot see how just 3 transistors can do that, because the circuit requires to be driven in push-pull with some gain on the in-phase (push) side. I need suggestions how to do that, using Si transistors, of course. The frequency range I need is 20 kHz to 60 kHz. In this range, ordinary op-amps can introduce unwanted phase-shifts unless the closed-loop gain is kept very low.

I am including the original article and the results of a Spice simulation. Original article Spice simulation

\$\endgroup\$
4
  • 2
    \$\begingroup\$ expand your zip locally, then attach any picture files, or if necessary screenshots of your display \$\endgroup\$
    – Neil_UK
    Commented May 26, 2022 at 11:20
  • 2
    \$\begingroup\$ John Woodgate - Hi, (a) As just commented, please edit your question & upload relevant image files (use Ctrl+G in the edit box, on a PC). If you reach the limit (2 files?) for a new user, then put them on a public share somewhere and some kind person will edit them into your question for you. (b) Please also add a clear question. Are you trying to understand how the circuit works? Or are you trying to build it (without germanium transistors?) and have a problem doing that? Please try to be as specific as possible about the question, and include any relevant context & constraints. Thanks. \$\endgroup\$
    – SamGibson
    Commented May 26, 2022 at 11:27
  • \$\begingroup\$ Thanks, Neil, but I don't know how to atatch, as i said. \$\endgroup\$ Commented May 26, 2022 at 13:02
  • \$\begingroup\$ Thanks, Sam. I can reduce to 2 files and do as you say. I thought my message was clear: I don't see how to make a 3-transistor amplifier that will produce 2 anti-phase outputs, the in-phase one being a little larger. I will use Si transistors, of course. When I see a circuit that does that, I will build it. \$\endgroup\$ Commented May 26, 2022 at 13:06

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.