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I'm trying to understand how to calculate resistance in simple mixed parallel and series resister circuit. Below is a question from a worksheet I've been playing with to better understand the topic (Question 5 ->Figure 6).

Simple Resister Circuit

I can see the 220Ω and 100Ω resistors are in parallel, but I do not understand how to break out and calculate the 470Ω and 330Ω resistors.

The answer given is 80.54 Ω, but I cannot seem to reach this on my own.

How do I calculate the resistance between points A and B?

Source: AllAboutCircuits.com - Series-Parallel DC Circuits Worksheet

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Try re-drawing the schematic:

schematic

simulate this circuit – Schematic created using CircuitLab

Hopefully the solution will be obvious once you do so (comment/ask if it's not).

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  • \$\begingroup\$ This was very useful, thank you. Will absolutely try redrawing first in the future. Next on my list is LaTeX, but here is what I ended up with that worked exactly as expected: Resistance = (1/((1/((((1/((1/350)+(1/470)))+220)))+(1/100)) \$\endgroup\$ – Citricguy Mar 25 '13 at 6:03
  • \$\begingroup\$ You're answer led me to another question regarding the location of the 470 ohm resistor. electronics.stackexchange.com/questions/62263/… \$\endgroup\$ – Citricguy Mar 25 '13 at 6:42

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