Suppose we have this circuit
simulate this circuit – Schematic created using CircuitLab
How to do nodal analysis for this circuit?
Is it $$5-\frac{5-V_{A}}{2}-V_{A} = 0$$?
or $$5-\frac{5-V_{A}}{2} - 2 \frac{5-V_{A}}{2} = 0$$
EDIT
By
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Sign up to join this communitySuppose we have this circuit
simulate this circuit – Schematic created using CircuitLab
How to do nodal analysis for this circuit?
Is it $$5-\frac{5-V_{A}}{2}-V_{A} = 0$$?
or $$5-\frac{5-V_{A}}{2} - 2 \frac{5-V_{A}}{2} = 0$$
EDIT
By
You need to introduce \$I_M\$ into the fray or you'll just get 0 = 0 and that helps nobody: -
$$5 = 2\cdot I_M + V_A$$
Where \$V_A = 2\cdot I_M\$ (as per the dependent source) so: -
$$5 = 2\cdot I_M + 2\cdot I_M$$
And, \$I_M=1.25\text{ amps}\$ and \$V_A = 2.5\text{ volts}\$. Sanity check: -