As with every IC, you should find out as much as you can about what's inside it and how it works to get the best from it. Such info' comes from datasheets, application notes, white papers, example designs etc.
Here, the Texas Instruments 74293 datasheet shows the below internal circuit. It shows two clocked counters made from 4 JKFFs: a 1-bit counter and a 3-bit ripple counter. The four JKFFs share an asynchronous reset, active when R0(1) and R0(2) are both asserted.

The question wants to make a single 8-bit ripple counter from two 74293 ICs, which is straightforward. Using 74293 ICs U1 and U2, the connections are:
clock --> U1.INPUTA
U1.QA --> U1.INPUTB
U1.QD --> U2.INPUTA
U2.QA --> U2.INPUTB
The 8-bit counter output is then, from MSB to LSB:
U2.QD, U2.QC, U2.QB, U2.QA, U1.QD, U1.QC, U1.QB, U1.QA
For the asynchronous resets, you can connect both R0(2) pins HIGH and both R0(1) together as a single counter reset signal, the active-HIGH RST_CTR
.
RST_CTR
can be driven by an existing signal in your design, such as a counter clear or power-on reset. If you don't have the latter, one by produced by a simple RC with a strong diode to protect RST_CTR
(and its weak internal diode) by discharging the capacitor on power-down. An example is shown below.

simulate this circuit – Schematic created using CircuitLab
The RC values must make the RST_CTR
rise time lag the supply rail's rise time, while keeping the rise time as fast as possible. It must ensure that RST_CTR
is held at a valid logic HIGH for (e.g.) 1 us after the supply rail has reached the 74293 min. operating voltage. Purely example values are shown. Calculate your correct values using the datasheet.
Ideally, the counter clock should not have a rising edge as RST_CTR
goes from asserted to negated. Otherwise, some counter JKFFs may go metastable. They will recover to valid levels before the next clock edge unless the clock frequency is above a maximum. Again, that's a datasheet analysis exercise.