I am using a PHY that has internal pull-ups and pull-downs on certain pins.
On this particular pin, there is a pullup that the datasheet says can range from 33 kΩ to 93 kΩ.
For the entire range, I would like to calculate the actual voltage that will be on this pin. The pin is pulled up through this internal resistor to +2.5 V. I am assuming that this pin will be at something less than +2.5 V due to some leakage current through the resistor.
The datasheet mentions that there is 85 μA of leakage current (including the pullup resistor), but I am not sure how to use this value since 85 μA * 33 kΩ = 2.8 V which doesn't make sense.
Can someone help me figure out the voltage on this pin for the 33 kΩ to 93 Ω range?
The datasheet can be found here.