I've been trying to solve a book problem from Hayt, et al. Engineering Circuit Analysis (8th Ed.) —Practice Problem 11.9. Practice 11.9

And here's my latest attempt, I just can't see what I'm doing wrong, why I don't get the answers from the book. Probably it's just some blunder I don't realize I'm making like a sign or a rule poorly applied. Please help me understand what I'm doing wrong.

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\$V_1\$ is the voltage of the 1 \$\Omega\$ resistor.

  • 1
    \$\begingroup\$ To point you in the right direction, I would combine impedances to find I1 first. This should give you 5.16A∠25.46 which gives you the correct value for the power consumed by the 1 Ohm resistor. \$\endgroup\$
    – vir
    Commented Jul 26, 2022 at 23:07
  • \$\begingroup\$ @vir thank you, but I have a question with respect to my nodal approach, I think I'm doing wrong the relation for the voltage of the 1 Ohm resistor, right? \$\endgroup\$ Commented Jul 26, 2022 at 23:17

1 Answer 1


The input impedance of the circuit is given by:


Where \$\alpha\space\text{||}\space\beta:=\frac{\alpha\beta}{\alpha+\beta}\$.

So, the input current is given by:


So, we get:



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