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I was trying some simulations and tried the below circuit.
My question is, how is the below marked voltage negative (-3 V)?
I thought like, since there is a diode, there will be approximately 4.3 V across the capacitor and 0.7 V across the diode. Why is this not the case in the above circuit?
Simulators can't model everything, they simulate only within their limits and according to the models of components they have, and using discrete finite time steps.
Your circuit has ideal voltage source, ideal wires, ideal capacitor and ideal diode, simulated with discrete time steps. And it is not known which capacitor simulation you have selected.
As such an ideal circuit like you have drawn can't exist in real life, simulating it will end up in non-real life result in simulator.
