Could I get a MOSFET to behave like a BJT (with respect to the large signal and hybrid-pi model) if I just tie a resistor from gate to source?
0
Add a comment
|
1 Answer
\$\begingroup\$
\$\endgroup\$
No.
- A BJT has a very definite relationship between VBE and currents. MOSFETs have lower gm (dI_drain/dVGS) which is not as precise as BJTs.
- High voltage MOSFETs have different characteristics as VDS exceeds about 5-10 V (LDMOS pinch off); no such breakpoint exists in NPNs.
- BJTs have non-zero VCE as IC goes to 0; MOSFETs behave like resistors.
- The current that flows in your R_GS is linear with VGS; a BJT is exponential. There is no definite relationship (like beta) between resistor current and drain current.
