We are using the MAX15162 "Circuit Breaker IC" (basically a high-side switch with current monitoring and start-up/MOSFET SOA protection), but don't understand exactly how its start-up process works.
In its datasheet it says that to keep the MOSFET in its SOA during start-up, it outputs a series of current pulses where the averaged startup current is 28 mA. This continues until either 1) the output is within 700 mV of the input (at which point it starts to enter normal operation mode) or 2) the start-up watchdog times out.
But if a load is resistive and draws more than 28 mA before Vout is equal to Vin, how is Vout ever going to reach Vin so that the IC enters normal mode?
Surely Vout would start at 0 V and start to climb. The 28 mA would start charging any capacitance on the output. But any resistive load would start drawing current too. Once Vout climbs such that 28 mA or more is going through the resistor, won't Vout stop climbing? Obviously I'm not understanding its behavior correctly.