Suppose you have an AC circuit and you connect a light "in parallel" on the live wire. Essentially a loop on the live wire. How does electricity flow in such circuit? The light would turn on, but I struggle to understand the potential differential.
I've drawn this horrible schema to (hopefully) clarify my question.
Sorry for making you look at that...
The potential differential between B1 and B0 is obvious, but between B3 and B4? Between J1 and J2 there is potential differential, but so there is between B4 and J2.
I am aware of my lack of knowledge, but I cannot measure the ridiculousness and/or simplicity of my question, so be ruthless, but please someone point me in the right direction.
P.S. this question is based on a DIY project that I though would explode but didn't :)
The diagram above is an over-simplification which hides my real question: how is this not blowing up? Thank you to all of you who answered, I'm going to try to be more specific.
In this diagram you can see two lights. R1 is connected on the standard (at least from my experience in the UK) loop circuit. The live wire to R1 is broken by a switch using the neutral cable to connect back to the light. When S1 is ON, R1 is on and the blue/neutral cable coming from S1 is effectively live.
I wanted to try to get another light from the only cable I had access to (I know, don't touch if you don't know...), so I hooked another switch and a light to the cable before realising that the neutral is not actually a neutral.
As I hope the schema shows, now I have an extra switch S2 that bypasses S1 turning on R1 and R2. The behavior I cannot explain is that when S2 is ON, S1 can be flip ON/OFF without apparent effect.
It might be worth mentioning that both lights are LED so extra electronics might be in place.
Tomorrow I'll try to take some pictures but sadly most parts of the cable are inaccessible which theoretically could be hiding some other connections or components.
Thank you again to everyone!!!