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In fixed bias circuit enter image description here

I calculated voltage gain by this :

I measured the DC response in simulation as:

Ic = 3.73 mA Ib = 15.7 uA Vc = 11.3 mV Vbe = 824 mV I calculated re (ac emitter resistance)

re = 25mV/Ic = 25mV/3.73 mA = 6.67 ohm I calculated voltage gain from

A = (R1//R3)/re = 4761/6.67 = 713

Which Multisim voltage gain is not match my calculation. And I asked question about this and found answer that :

"For a fixed bias amplifier like this the correct (and overkill formula) should be

Av=−α∗(RC//RLoad//RB)/re

where

re=Vth/Ie=kT/(qIe) α=0.996 "

Which model did they use in second voltage gain? And where does this equation from?

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    \$\begingroup\$ What is the emitter connected to? \$\endgroup\$
    – qrk
    Commented Oct 23, 2022 at 6:36
  • \$\begingroup\$ @qrk Sorry , emitter connected to ground. \$\endgroup\$
    – Heroz
    Commented Oct 23, 2022 at 6:45
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    \$\begingroup\$ The answer you have "found" is wrong. Such a base resistor RB (in your drawing R1) has no influenbce on the gain. I \$\endgroup\$
    – LvW
    Commented Oct 23, 2022 at 9:39

1 Answer 1

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The mentioned gain formula A=-(Rc||RL)/re=-gm*(Rc||RL) is a rough expression only. It neglects the finite output resistance rce of the transistor (not an ideal current source) as well as some other non-dealities which are covered in the Ebers-Moll equations (core of the BJT models used in the simulators).

See here: Measuring BJT (Ebers-Moll) parameters

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