In my design I want to measure the current going through a load with a shunt resistor. Based on some preliminary calculations, I've selected WSBS85181L000JK34 from Vishay. Being my first time using such high power shunt, I'm confused about the mounting system: does it need to be soldered on the PCB or screwed down with a nut and a bolt on opposite sides of the PCB?
Also, that resistor has a notch on one side. Should it face the up or down to the PCB? My guess is that the middle part shouldn't touch the PCB, which is where the current sense lines would go.
For clarity, the max load to be measured will be 5A @ 5V (30W), so I selected a 36W (1mOhm) resistor to have some margin.
EDIT: Thanks to @brhans and @John D for highlighting my conceptual mistake. When choosing a shunt power rating one must think at the power dissipated by the shunt, not the load, so in this case I have 5A going through a 1mOhm shunt, which gives a power loss of P=I^2*R -> 25mW, so a anything higher than 30mW is prefectly suited for the job, certainly not a 36W shunt resistor.