He found an error of about 18%.
What is the error formula used in this example?
From section 1.5.1 of the book Design of PLLs by Behzad Razav.
\$\begingroup\$
\$\endgroup\$
2
-
2\$\begingroup\$ Ummmm... Equation 1.36 maybe???? \$\endgroup\$– Kyle BCommented Nov 24, 2022 at 7:30
-
2\$\begingroup\$ So show what you have considered so far. \$\endgroup\$– Solar MikeCommented Nov 24, 2022 at 7:41
Add a comment
|
1 Answer
\$\begingroup\$
\$\endgroup\$
If a target value is supposed to be 1.51 units, and you use an actual 1.25 unit thing, then your error is (target - actual) / target = (1.51 - 1.25) / 1.51 = 0.1722.
It appears your textbook rounded that to "about 18%", perhaps by calculating 1.25 / 1.51 = 0.8278, rounding to 0.82, which is 0.18 from 1.00.
answered Nov 24, 2022 at 7:58