I am trying to make a kicker solenoid. My circuit is:
12 V battery connected to DC step-up booster 300 V
diode A10A. The diode is rated for 10 A and 1000 V.
thyristor BTW69-1200 with external circuit (battery 1.5 V - resistor 1/4 W, 39 Ω). The thyristor is rated for 50A and 1200 V.
capacitor 1000 μF - 450 V
solenoid coil (3.6 Ω)
Since the capacitor will send about 60 A I thought the diode would burn out when tested, but surprisingly, it did not.
How it did not burn out while the current is 60A and this diode is rated for 10 A?
Is the back EMF current low and does it not follow Ohm's law?