How does changing the volume pot value affect output power?

The diagram I'm following for a basic TDA7297 stereo audio amplifier specifies 50 kΩ for its volume control, but I only have 10 kΩ and 100 kΩ dual pots.

If I use 100 kΩ I know I could halve it to 50 kΩ by adding a 100 kΩ resistor, but what happens if I use it as-is, and what happens if I use 10 kΩ instead? Would 10 kΩ limit the total output loudness? Somewhere I read changing values would not limit output but limit some frequencies, but I have no clue.

EDIT: source for input will be a cell phone

This one uses 10kΩ

But this one 50kΩ

From datasheet

• Interesting question that cannot be accurately answered with out more information. You need to post a link to the technical information on your amplifier board, the chip does not show a volume control. I suspect it is a voltage divider on the input of the AMP and should not matter but that is also depended on the signal source and its impedance.
– Gil
Dec 19, 2022 at 1:57
• @Gil just added the diagrams sir. Dec 19, 2022 at 2:29
• @AramAlvarez The input impedance of the IC is not less than 25 kOhm but in that vicinity. Given the cell phone (at least a few milliwatts of output into a headphone at full volume), you will be fine with a 10 kOhm pot. The cell phone expects a significantly lower load.
– jonk
Dec 19, 2022 at 5:31