I've just rewound a single-phase, 1/4 hp, 4-pole top-load washing machine motor identical to this one.
It was originally wound in AWG 22 aluminum wire, and I rewound in AWG 23 copper wire, which should have about 80-85% of the resistance of the original winding, which isn't so much lower that the capacitor value should be readjusted.
What I found strange is that its no-load current, with the original 40 μF capacitor, was too high. 2.8 A, 90% of rated current.
And it was heating horribly, it reached 100 °C in a couple minutes.
Then I noted something strange. By braking it with my hand, the current fell.
The current consistently fell, even at low speeds well below the breakdown torque, the current was still much lower, it fell to 1.9 A at its lowest.
What's the logic of this?
I never found anywhere online mentioning this behavior, and for all I know this makes no sense.
Perhaps these motors have a non-ideal behavior because of the way they're wound?
Instead of having an auxiliary winding with lower L/R ratio, it has two identical windings, same gauge, same number of turns, pitch etc.
It's wound exactly like an old two-phase motor would be wound, with two identical sets of windings made to be fed with phases in quadrature.
It's wound like that so it can be reversed by changing switching only one contact, changing which winding is fed through the capacitor and which is fed directly by the mains.
Or, perhaps, this happens because its capacitor is not optimized for nominal slip?
It's a permanent capacitor, so you'd expect it to be optimized for nominal slip, but as this motor needs to quickly reverse its rotation during the washing, it needs a decent starting torque too.
So perhaps its value is larger than that you'd use if this motor didn't have to do that and only ran in a single direction at nominal speed all the time, like fans do.