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I need a bit of help for my device schematic, more specifically for the status pins of the MCP73871. I am a beginner so I am trying to understand how to do it properly. The pins are PG, STAT1/LBO and STAT2. From my understanding, I can pull up both PG and STAT2 and connect them to my MCU. For the STAT1/LBO pin, if I want to use the LBO does it have to be connected to the battery?

My device will have a battery connected which is why I am using this component. I included my diagram as well.

enter image description here

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  • \$\begingroup\$ sorry, I don't understand the question. "For the STAT1/LBO pin, if I want to use the LBO does it have to be connected to the battery?" <- is this the question? I'm not sure why you would get the idea that STAT1/LBO had to be connected to the battery \$\endgroup\$
    – user253751
    Jan 16 at 18:47
  • \$\begingroup\$ Is J1 where you are connecting the battery? Because you have both terminals shorted together in your schematic \$\endgroup\$
    – PhippsTech
    Jan 16 at 19:26
  • \$\begingroup\$ @user253751 I saw an example online where someone had done that, hence my question. \$\endgroup\$
    – JediSpecter
    Jan 16 at 22:43
  • \$\begingroup\$ @PhippsTech Yes J1 is where I am connecting the battery. Should I remove the wire in-between both wires? \$\endgroup\$
    – JediSpecter
    Jan 16 at 22:43

1 Answer 1

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No, that pin will need to be connected to the ESP32 if you want to use it. It's just a low battery output. Be sure to pull it up to 3.3V since it's open drain if you want to use it.

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  • \$\begingroup\$ Okay I see, so I can pull all 3 pins to high and have them connect to GPIOs on my ESP32. Thank you. \$\endgroup\$
    – JediSpecter
    Jan 16 at 22:44

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