0
\$\begingroup\$

I need help for the design of on-air light interface. The DB15 connector output of console arc10 is 12 V, 200 mA (max). The load is on-air light bulb, 230 V AC. I'm considering the interface circuit between arc10 console output and the load to be the optocoupler with a triac.

Is it ok to just use a resistor voltage divider to convert the DB15 connector output 12 V DC 200 mA to a 5 V DC optocoupler input without any issue? What about the drawn current of the optocoupler input? What value of resistor to satisfy the optocoupler input drawn current.

\$\endgroup\$

1 Answer 1

0
\$\begingroup\$

You don't need a divider, you can just increase the value of the current limiting resistor in series with the optocoupler's LED. The resistance you need follows ohm's law: \$R=\frac V I\$. To compute \$V\$, subtract the forward voltage of the LED (taken from the datasheet) from your supply voltage. The value of \$I\$ (the optocoupler LED current) is also taken from the datasheet.

Alternatively, you can skip building your own triac-based switch and just buy a solid state relay (SSR) module. You can buy them with 12V inputs, which will allow you to connect it directly to your console without any extra electronics.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.