Here is a schematic from TI:

enter image description here

I also attached a picture of the schematic part concerned:

enter image description here

I do not understand why there is a common mode inductance. (But I know that there is a reason :) I just do not know why)

The input signal coming from the left are 12 V and ground. The input noise can be differential:

  • If I have long wire between the connector and the power supply delivering 12 V. Those wires are not twisted. In function of the size of the area of the loop (closed by the capacitor in high frequencies), if a magnetic field travels the loop, I can induce some noise current into the loop. So it is nice to add capacitor at the input to filter this noise.
  • Also in function of the noise coupled and of the intresec operating curent of the board, I can have some voltage drop due to current pulse and so a capacitor help to minimize the noise on the voltage source. So as shown the capacitors are useful. A inductor would also help to make a 2nd order filter. We can think that the common mode noise as a leakage inductance which acts as a "differential inductor". A 2nd order filter will so filter even more the noise from the long wire and the resultant inductance of the wire.
  • But why a common mode inductance? As stated, a common mode inductor have to filter the common mode noise. The board is not connected to the earth. The only thing that I can think is that there are "hiden" capacitors between the earth and the board and also after the inductor:

enter image description here

Nervertheless, If I can understand that the ground plane "AGND" can have a "large capacitance" from AGND to earth ground as the area of the ground plane "AGND" is relatively large. I do not really understand how the 12 V has a large capacitance between its potential and the earth ground. It also concerns all other signals not connected to the ground plane "AGND". It will be hard to locally bypass the common mode noise just after the common mode inductor if the capacitance between the earth ground and the 12 V potential is low.

Is there an other reason for using a common mode filter at this place?


5 Answers 5


Manufacturer link: https://www.ti.com/tool/LMG342X-BB-EVM

It's not even clear that they've correctly labeled it as CMC. The component appears to be a dual winding inductor: DRQ Inductor data sheet - Eaton, rated for over an ampere at saturation. It might be wired for DM filtering instead (in which case there is still some leakage inductance which manifests in CM); though why they chose such a large value for that purpose, I don't know. It could still be used as a CMC, but it's peculiar that it's such a small value (~mH are available).

Probably it just doesn't matter. We can disabuse the need of EMC approvals as eval boards are unregulated. The only purpose here (if any) is keeping test equipment happy. And with respect to that purpose, I would guess this rather mediocre board -- which only serves as a carrier, plus some support components, for the actual inverter itself -- can't do much to improve the EMC of the daughterboard as it is, considering the few pins and no interleaving on their connection.

That is, the EMC equivalent circuit in use will be with some probes connected to the daughterboard, which is at some AC (RF) voltage with respect to the main board, due to switching currents flowing through the supply/ground return paths. (The board-to-board pins will contribute some 5 nH or so of inductance, minimum.) Scope probes will read the sum of actual signals plus this CM interference (plus some inter-probe coupling as their ground-return paths aren't free from inductance either -- depending on how directly connected they are, vs. using ground clip leads). Probably some CM inductance on the HV side, and output/load side as well, would be further appreciated. It's not clear why they chose one but not the other connectors.

Just to speculate:

An output CMC is perhaps the least important? But I would imagine many users of this product would have further equipment such as a SMU, or EUT -- more than just a passive resistor, say. The input might have an isolation transformer, but unless one is careful to get a low-capacitance kind, those can have significant (100s pF) CM capacitance as well. Whereas the low voltage input I suppose is most likely a common-ground bench supply, making CM the highest priority on that connector.

In any case, probing switching circuits during testing is tricky business in general. I usually have a few CMCs, ferrite cores and snap-on beads handy during my own testing; rarely if ever are they properly effective, but most of the time it's enough to see the interfering signal (a burst of noise or ringing, say) change amplitude or frequency with the introduction of the ferrite bead, so I can mentally subtract that noise from the signal itself.

But this is also quickly getting into matters of opinion, and also a bit off topic.

EMI Environment

EMI equivalent diagrams

Some rough doodles to help illustrate.

The metal table is a ground plane, making things easier to represent. This is the best case where we can invoke some kind of absoluteness to voltages in the system. That is, we can have some meaning behind "what's the voltage between scope GND and plane?"

"System" means everything connected, to the extent we need to know about it for purposes of response / behavior. Filters and shields are used to reduce the effects of outside elements, like mains wiring, or...cars driving by the facility. Thus we can truncate the scope, keeping our consideration local.

Filtering and shielding basically revolves around resistance, terminating any unwanted modes and dissipating incident and reflected waves. A pure LC (lossless) system isn't quite feasible, because the Q factor could approach infinity and therefore any nonzero coupling (even through otherwise negligible modes like quantum tunneling) can still transfer energy. Loss ensures that, whatever quality of shielding we have (absorptive or reflective), the signals on either side stay separate.

So, for a line filter, we might have LC elements facing the input/output sides, and termination resistance in the middle. For a mains filter, the resistance needs to be AC-coupled so it only applies to high frequencies (can't be shorting out a mains supply with 50 ohms everywhere, that would be rather inefficient..), and that's fine because at low frequencies, we can measure voltages reasonably effectively.

Regarding the table, we can still wave our hands about a plastic (or poorly constructed metal) one, but any attempt at measuring voltage becomes completely path-dependent, i.e. for any two points you put your probes between (assuming an ideal floating oscilloscope), the exact positioning of the probe leads themselves matter -- in some locations and orientations, they'll pick up more fields from nearby one element, or less of another.

We use a ground plane to short out a lot of those field lines, and we keep cables and equipment spread out on it, so the fields from each element, cable, whatever, have little coupling between, and the field lines around them are more straightforward. This gives us some path independence, and perhaps even more importantly, defines our path for us relatively specifically: simply probe straight down from the element, to the plane, in a vertical (plane-perpendicular) path.

We can also use coupling networks (current clamps, capacitive clamps, etc.) to measure signals on cables in an even more standardized fashion.

Anyway, as far as the noise source here, there will in general be some AC voltage between connectors on the board (EUT, Equipment Under Test), and it is that voltage which creates current flows through the scope probe and other supporting equipment loops. Which may be returned through the ground plane (if bonded to it), to each other (say by communications cables), or through the mains network (or LISN or other filter, if in use for the test equipment).

More specifically, the voltage between connectors arises as inverter switching current, flowing through supply/return inductances (Lstray) and thus dropping some voltage between them. The motherboard in question here makes little or no attempt to reconcile these voltages, and perhaps the one CMC is an attempt to limit one of the connectors' interaction with the overall EMI system (by vastly increasing the inductance to it, thus reducing its share of CM currents).

Note that CM cable inductances are on the fractional to singles µH order of magnitude, for cable lengths that would fit on a table anyway. So the 47 µH has marked effect with respect to (WRT) those. But being inductive rather than dissipative, it may simply shift a resonant frequency: consider the effect of equipment that is isolated so has some capacitance from mains or earth or chassis to the EUT terminals. (Which connects with your other recent question, it seems.)

This is, in part, why CMCs tend to have high losses, i.e. a broad resonant frequency. (Note that the resonant frequency of a 2-terminal component, is where its impedance is resistive.) They also need high impedances (~kΩ) to have useful effect compared to the ~100 Ω impedances of cables in the common mode.

  • \$\begingroup\$ Thank you for your answer. Nevertheless I have some difficulties to understand what you say :'(. Could you please illustrate your explanation by some schematics ? You said that the possible common mode noise comes from the probes that are connected to the earth of the oscilloscope. So for example if I want to measure the drain to source voltage across the high side switch and I put the "ground" clip of the probe to the source (switching node). As this point is floating (swiching node) it means that the circuit inject current through the ground probe to the earth and it may come back easily ... \$\endgroup\$
    – Jess
    Commented Feb 26, 2023 at 9:41
  • \$\begingroup\$ depending on what is value of the common mode inductance and capacitor on the common mode filter or parasitic capacitor ? The same problem appear at the low side switch and is due to the parasitic inductance that can achieve high dv/dt. Or just because some common voltage will appear between the ground plane of the board and the earth board due to parasitic capacitance between the ground plane and the earth for example \$\endgroup\$
    – Jess
    Commented Feb 26, 2023 at 9:50
  • \$\begingroup\$ It is interesting what you said at the end of your answer. Do you have some documentations on this subject that I could read ? I would reallly appreciate to better understand what is happenning \$\endgroup\$
    – Jess
    Commented Feb 26, 2023 at 9:55
  • \$\begingroup\$ @Jess Added. For the case of a scope with isolated input channels, or "lifted ground" (do not recommend for voltages like these!), or a handheld portable, there is still some capacitance from the probe cable, scope body, or across its isolation barrier, which closes the loop through ground or other means, making a -- probably LC resonant circuit, hence the squigglies on such a waveform. \$\endgroup\$ Commented Feb 26, 2023 at 11:26
  • 1
    \$\begingroup\$ @Jess Snap-on on the probe cable (around all conductors). Often multiple turns, or a larger core with the probe cable looped through it many times. Again, usually it doesn't reduce the noise level much in the reading, but it still changes the frequency, helping one identify what's going on in the system, and what's "real" or not about the measurement. \$\endgroup\$ Commented Feb 26, 2023 at 13:29

Earth referenced common mode signals are always present. They are often modelled as being conducted through a capacitance in parallel with a resistance.

We and our circuit boards are immersed in electric fields generated by the power distribution system, radio transmitters, and other natural sources like the sun.

When every point in a circuit has the same phase and magnitude relationship to the source, then the source is considered common mode. We say that the circuit is “floating” on the common mode signal. We also say that every point in the circuit is “balanced to earth”, “balanced to ground” or “balanced to the common mode signal”.

If one region of the circuit is “out of balance”, then a differential signal is created from the common mode one resulting in noise and interference.

The number one defence against common mode to differential conversion is balance to ground.

Twisting wires allows magnetically induced voltages to alternate in differential polarity thus cancelling along the wire. Electric fields induce common mode signals that can cancel due to balance to ground. The tighter the twist the better is the balance to ground, A coaxial shielding will further improve balance.

The common mode choke isolates unbalanced circuitry from balanced circuits. This ensures that the load on our twisted pair can be designed to maintain balance. This input circuitry can do double duty as a differential filter.

If the other side of the choke is also balanced, then there is little reason for including the choke.

A clean reference plane provides balance to ground by forcing every point of the circuit to have the same impedance to the plane. It is important to have a low inductance and resistance throughout the plane.

In short, to reduce the effects of common mode signal look to balance to ground as your freind.

  • \$\begingroup\$ Thank you for your answer. I missunderstand why the tighter the twist, the better is the balance to ground. If I have a really tigh twisted pair of wire, but a large loop between those wires and the ground, I will still have a possible noise that can couple whatever if the pair is well tighted or not ? \$\endgroup\$
    – Jess
    Commented Feb 26, 2023 at 9:23
  • \$\begingroup\$ Also, I agree with you on the fact that the common choke isolates unbalanced circuitry from balanced circuits by increasing the impedance path for common mode signal. But the current still have to pass somewhere and we go back to the schematic that I have drawn with the hidden capacitors ? \$\endgroup\$
    – Jess
    Commented Feb 26, 2023 at 9:28
  • \$\begingroup\$ What current are you referring to? \$\endgroup\$
    – RussellH
    Commented Feb 26, 2023 at 14:34
  • \$\begingroup\$ Common mode current ? \$\endgroup\$
    – Jess
    Commented Feb 27, 2023 at 10:42
  • 1
    \$\begingroup\$ The hidden capacitors are implied in my first paragraph. They are often called stray capacitance to ground/earth. Current “flows in a closed path or circle. Breaking/opening the path anywhere along its length will stop the current. The common mode choke accomplishes this. The common mode voltage is still coupled through the stray capacitance/resistance, but there is no current because the common mode choke opened the circuit . \$\endgroup\$
    – RussellH
    Commented Feb 27, 2023 at 13:03

The common-mode choke is indeed questionable. Todd Hubing said once in an Altium interview that he thinks that CMC are massively overused because their manufacturers advertise them a lot.

Common-mode noise can be an issue though. Consider that the 12V input has a common-mode reference to earth. That board could pick up common mode voltage and common-mode current would run down the 12V cable pair.

The CMC inhibits this current reducing the radiation from the supply cable. It makes the board more floating.


In my experience with industrial design, CMC are most important for preventing high frequency radiated emissions from the equipment being powered, rather than stopping noise getting in.

Once you get above say 10Mhz, even small capacitances to ground act as low impedances, and it is therefore very easy for desired internal signals to be accidentally converted into common code interference on the supply lines.

Put another way, if you are shielding your equipment to stop radiated RFI, you need the CMC to stop the noise sneaking out along the supply lines.


It's almost certainly there to prevent conducted emissions (CEs) on the input power cable. Conducted emissions can also lead to radiated emissions (REs), if the input cable is not shielded (which most are not).

From Eric Bogatin's Rule of Thumb #31, it only takes 5 uA of common current to fail an FCC part 15 Class B EMC compliance test.

CMC's are fairly standard practice in our industry, since we do not want the added weight that shielding a power cable would entail.

Each individual power supply may not have a CMC - it may be part of a so-called dirty filter box that filters the power coming into the unit and distributes that prime power to the individual power supplies.

Finally, the amount of attenuation that a CMC needs to provide is determined after appropriate analysis and modeling has been done of the entire power system.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.