I guess people have asked slightly similar questions to mine before, but I still haven’t been able to find a complete answer as to WHY the current doesn’t increase even when the voltage in a circuit does.
When batteries are connected in series, their voltages add up. Now let’s imagine we put these batteries in a circuit with a load, but we do this by first connecting the load to ONE battery and finding the I (current,) then after that, adding the second battery in series BUT keeping the load and everything the same. By V=IR, wouldn’t this mean that since we’ve doubled the voltage in this case that the current would also be doubled, considering we keep the resistance (ie load) the same? I’ve done a sketch of an example, attached below:
Please provide a straight-to-the-point answer if you can. I don’t know why this has been bugging me so much but if I can understand this then I’m confident that I’ll be able to grasp pretty much everything else about electronics.