# Short circuit parallel to current source explanation

I was given this circuit in a circuit analysis course and found out using KCL/KVL that all the currents in blue are zero and Ix = -2A. I understand that the current source is connected with both terminals to the same node, so the 2 amperes is coming in and out of the A node.

I know that in a test my professor wants a more elaborated answer, so I though about some different ways of looking at the circuit:

1. The voltage between any given resistor is always zero, because independently of resistor association, all of the resistors would be connected to the same potential, given a reference, because there can only be one voltage in a node.

2. The node A can be thought of as a resistor with a value of zero, and because no other already existing resistor would be connected in series with all of the 0 ohm resistors, all of the circuit acts like a big current divider, and because I(out) = I(in) * EquivalentResistance/(EquivalenteResistance+0), I(out) = I(in) all of the current would pass through the 0 ohm resistor.

Are these valid ways of looking at the circuit? Is there any other simpler way of looking at it without doing all of the KCL and KVL calculations?