5
\$\begingroup\$

I'm doing a little bit of experimentation with a glass of water and a 9 V battery. I added a little bit of salt to the water, and I measure the resistance in the water from probe to probe to be ~60 kΩ. Ohm's law tells me the current (given negligible additional resistance in wires, I'm using short copper wires) should be ~150 µA if I connect the terminals of the battery through electrodes separated in the water. When I drop the wires in there I can visibly see small bubbles forming on the electrodes, which tells me that current is indeed flowing, and chlorine and hydrogen gas are being formed.

However, when I then proceed to detach one wire from the battery and connect it to one of the probes of the multimeter, and then connect the other probe to the battery instead (connecting the multimeter in series with the circuit, as you're supposed to to measure current), then nothing happens. The multimeter is supposed to be able to measure to a resolution of 10 µA, so ~150 µA should definitely be within its detectable range. However, it's not just that there's no measurement, but there are no bubbles forming, and thus presumably no current (or at least not nearly as much). I've connected the probes together measuring resistance to ensure that no fuse has blown, and it's measuring only ~5 Ω, so there's clearly a connection, and this resistance should be negligible compared to the ~60 kΩ in the water.

So, why isn't there any detectable current flowing when I'm doing this?

Here's a schematic, as requested by several commenters:

enter image description here

On top is the connection with just the battery and wires in the water, below is the multimeter connected in series with that circuit.

The multimeter is a Biltema 15-133.

\$\endgroup\$
1

2 Answers 2

11
\$\begingroup\$

Why is my multimeter not measuring current?

Because the internal 200mA fuse is blown. Check the manual, page 4 (på svenska, eller s.7 på norska), section "Byte av multimeterns batteri och säkrningar", for hints on how to access the fuse.


According to the manual for Biltema 15-133, your multimeter has a 200mA fuse in the low current measuring circuit.

Whenever you set the range dial to one of the following settings:

  • 2000μA,
  • 20mA,
  • 200mA

and there is a voltage source attached to the input terminals, the fuse will be blown unless the voltage source is very weak.

Since this is a lousy design for a meter, I can almost guarantee you turned the range selector through those ranges while measuring voltage at some point, and the 200mA fuse is blown, and that's why the meter doesn't measure current.

As far as I'm concerned, until you verify that the 200mA fuse is not blown, you're wasting your time.


Reproduce the result below first, without worrying about water and salt. If you can't measure the current in the setup below, there's something wrong with your meter. Most likely a blown fuse or operator error.

Again, forget about water and salt until you can get current measurement to work at the 0.1mA DC level.

schematic

simulate this circuit – Schematic created using CircuitLab

\$\endgroup\$
7
  • 6
    \$\begingroup\$ @Kubahasn'tforgottenMonica: I managed to pry the multimeter out of its casing, unscrew it, and find the fuses; one of them is indeed blown, and this offending blown fuse reads "0.2A 250V". Mystery solved. Whether or not I blew it or someone who used it before me did remains unknown, but at least now I know how to avoid blowing it in the future. \$\endgroup\$
    – Outis Nemo
    Commented Apr 5, 2023 at 5:56
  • 2
    \$\begingroup\$ Without a fuse, if your meter is still measuring DC voltage properly, consider battery - water probe - water - water probe - 10K resistor - back to battery, then measure voltage across the 10K, do the calculation. \$\endgroup\$
    – jonathanjo
    Commented Apr 5, 2023 at 9:03
  • \$\begingroup\$ @jonathanjo: That's a great suggestion; however, I don't have any resistors lying around, but maybe if I can get hold of some at some point I can try checking that way. \$\endgroup\$
    – Outis Nemo
    Commented Apr 5, 2023 at 9:31
  • 5
    \$\begingroup\$ @OutisNemo If that meter was at school and used by students, it's guaranteed that fuse will be blown about once a week :) \$\endgroup\$ Commented Apr 5, 2023 at 14:01
  • 3
    \$\begingroup\$ This is why multimeters ought to have four jacks for the probes. Putting mA measurement on the same jack as voltage measurement is just asking for trouble. \$\endgroup\$
    – Hearth
    Commented Apr 5, 2023 at 15:07
8
\$\begingroup\$

This was an excellent experiment in many ways. Correct observation of basic phenomena, good suggestion of underlying science, correct set up of measurement, diagrams with all essential information, inference that something unexplained has happened, search for explanation.

The first rule of science is actually: reproducible or nothing. As Popper put it: "non-reproducible single occurrences are of no significance to science”. And you certainly can't reproduce this result with lots of meters.

And as a lab maxim: when you changed the circuit to do the measuring, do you actually have the same circuit?

In many labs I've worked in, we used the word "heisenberger" for effects caused by the act of measuring.

heisenberger, n. any surprise change introduced by the measuring equipment, after Werner Heisenberg's principle about measurement altering the observation. Often drawn as 🍔, hence often spelled -urger.

schematic

simulate this circuit – Schematic created using CircuitLab

If at all possible, have two meters, so that when you get a surprising result you can cross-check. Which actually is a general rule, especially in electronics: If at all possible, have two of each thing, so that you can cross-check when something surprising happens. Is my battery faulty? Does this wire have a break? Have I blown up this transistor?

\$\endgroup\$
7
  • \$\begingroup\$ love your schematics \$\endgroup\$
    – Neil_UK
    Commented Apr 5, 2023 at 8:52
  • \$\begingroup\$ @Neil_UK I'm sure you can tell I've seen a lot of variants of this diagram. \$\endgroup\$
    – jonathanjo
    Commented Apr 5, 2023 at 8:57
  • \$\begingroup\$ That's definitely a good idea. I should've suspected that the problem was with the meter, but the fact that it still appeared to give good measurements otherwise threw me off; I was unaware that it not only had two different ports for different currents, but also two entirely different internal circuits for its different measurements. \$\endgroup\$
    – Outis Nemo
    Commented Apr 5, 2023 at 9:28
  • \$\begingroup\$ @OutisNemo It's really worthwhile understanding what's inside a multimeter: have a look at this tutorial \$\endgroup\$
    – jonathanjo
    Commented Apr 5, 2023 at 9:55
  • \$\begingroup\$ @jonathanjo: It sure is; in this case I thought I had a fair grasp on it, but what threw of was, as I mentioned above, that separate circuits were being used for the different measurement settings. I don't think there's anything in that tutorial which addresses this, it only deals with how each function works if I'm not mistaken. \$\endgroup\$
    – Outis Nemo
    Commented Apr 5, 2023 at 10:19

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.