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I wish to monitor a battery using an Arduino. I can successfully measure the value using an Arduino via its Analog port, which gives me a 1024 bit value range.

Where I'm stuck is how to allocate that 1024 bits to a small portion of the voltage range to improve the accuracy.

By using a simple resistor divider I can measure the battery voltage from say 14.5V to 0V and the 1024 bit are therefore spread across that.

What I would prefer to do is only measure from 11.5V to 14.5V and have the 1024 bits associated with that range, make it more accurate.

I can't for the life of me think of how to do that.

Any help would be greatly appreciated.

Thank you.

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    \$\begingroup\$ Have you considered a differential amplifier, measuring with respect to an offset (e.g. 11.5V)? \$\endgroup\$ Apr 7, 2023 at 4:14
  • \$\begingroup\$ it's 10 bits, not 1024 bits \$\endgroup\$
    – jsotola
    Apr 7, 2023 at 4:42
  • \$\begingroup\$ Yes it is 1024 values from 10 bits. \$\endgroup\$
    – Markus
    Apr 8, 2023 at 5:24

1 Answer 1

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schematic

simulate this circuit – Schematic created using CircuitLab

This circuit will produce 0-5 VDC with an input of 10-15 VDC.

Battery voltage expander

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    \$\begingroup\$ Thank you for the very detailed and helpful answer, that's exactly what I was after. \$\endgroup\$
    – Markus
    Apr 8, 2023 at 5:27

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