1
\$\begingroup\$

I have been working with two 12 V lead-acid batteries in series. Accidently, we kept them turned on for a day or two and one of them drained to ~3 V and the other to ~8 V.

I immediately charged them, but they get charged and drained super quickly. I read about recovery charge on this forum, but my charger doesn't seem to have a recovery charge function.

Also, sometimes it gets charged to 16 V on balance charge. Can those batteries be recovered or should I replace them?

\$\endgroup\$
4
  • 1
    \$\begingroup\$ Do you mean "lead acid"? They fail rapidly when heavily discharged, and most likely now need to be replaced. \$\endgroup\$
    – Tim Williams
    Apr 9 at 4:22
  • 1
    \$\begingroup\$ Lead acetate you say? Perhaps you could turn them into solar cells sciencedirect.com/science/article/abs/pii/S2211285519310948 \$\endgroup\$
    – Bruce Abbott
    Apr 9 at 4:48
  • \$\begingroup\$ Sorry for mistake I meant lead acid battery \$\endgroup\$
    – mrbeast
    Apr 9 at 17:05
  • \$\begingroup\$ Depends. If you charge them up, preferably to 16 V, let them bubble a little and refill any lost water (distilled), they may very well be serviceable. Do you have access to any ESR or load tester? \$\endgroup\$
    – winny
    Apr 9 at 17:11

1 Answer 1

Reset to default
0
\$\begingroup\$

There was no way to recover it. That battery went dead. Used it for other minor application and bought new battery for my original application.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.