# Need comments and ideas for LED flashlight project

I'm thinking about making a simple LED flashlight.

After doing some research, I think I'm going to use some 5 mm 12 Cd white LEDs with 3.6 V drop which can pass 20 mA. I'm not yet sure how much LEDs I'd need, but for now, I'm thinking about 5 or 10.

For power supply, I was thinking about single 6LR61 battery or 4 serially connected LR6 batteries or maybe even two serially connected 6LR61 batteries (but I'd like to avoid that as 6LR61 are pretty expensive here).

The 6LR61 batteries popular here according to data sheet have capacity 550 mAh while LR6 have capacity of 2600 mAh. Minimal voltage for 6LR61 is 4.8 V and 0.8 V for LR6. Since LR6 batteries have considerably higher capacity, I'm most likely going to use them, unless you provide a reason why to go with 9V battery. Also, if I serially connect batteries, would pack's capacity increase?

As for circuit itself, I was thinking something like battery pack with a switch serially connected to it. I'd the use parallel connection to connect a number of branches consisting of a resistor and LED to the switch on one end and battery pack on the other end.

However I'm concerned about energy usage. I'll have lots of resistors and each one will consume some energy. If I go for 9 V option or even 18 V option, I'd reduce amount of energy wasted by resistors, since I could connect several LEDs serially with a single resistor.

Another point which bothers me is what type of resistors to choose. I'd like to use up as much of the batteries as possible and have device work as long as possible. I've been experimenting with results form http://ledcalc.com/, but I'm still not certain what to choose.

EDIT 1
Another idea: Would a 555 timer plus a transistor as a switch be a good choice for making device PWM controlled?

• That LED calculator is pretty slick! I like how it shows the power wasted in the resistor along with power used by the LED. – DarenW Nov 12 '10 at 16:32
• 9V batteries are rubbish capacity wise - use AA's/LR6, much better. – Thomas O Nov 12 '10 at 17:57

Well, let's analyze the circuit. We know that the power required in a DC circuit is:

P = Vsrc * Iout

We know that

I = (Vout - Vled)/R

and the power delivered to the LEDs is all that matters, so we want to maximize

Pr = (Vout - Vled) * I = (Vout - Vled)^2/R
Pled = Vled * I = Vled * (Vout - Vled)/R

Clearly, we want to minimize Pr and maximize Pled. We can do this without decreasing the current by reducing R and making Vled close to Vsrc.

This is accomplished by putting the LEDs in series.

However, your battery (isn't the 6LR61 a 9V battery?) will go from some nominal voltage (ex 9V) to a lower voltage - 9Vs are spec'd to be dead at 4.8V. This means that a passive solution will go dim while there's still charge left in the battery. For your original schematic, that might mean that you'd end up below the minimum current to turn the LED on, or for the series version, the voltage might go below the diode forward voltage.

A simple way to extract more brightness with the same power is to pulse the LEDs - Human eyes percieve blinking light to be brighter than continuous light, even if the average power is the same. A 555 timer or other oscillator/switch combination will be able to do this, no microcontroller required. Try playing with the duty cycle and frequency of your LEDs to see where it looks the brightest - You may be surprised!

Also, a switching power supply can increase the efficiency of your regulation circuit to 80, 90, or even 95%. However, that will drive up the cost and complexity of the design, and may not be necessary.

• 6LR61 is 9 V battery. As for 555 circuit, I was thinking about using something like TS555 since it has wide voltage range for input. I'm also debating on 9 V battery versus 4*1.5 V pack. LR6 appear to have higher capacity then 6LR61. Wouldn't they work longer? According to ledcalc, I'd get ~10 h with simple 9 V circuit and ~32 h with simple 6 V circuit. – AndrejaKo Nov 12 '10 at 17:08

One idea is use a microcontroler, so you can drive the leds via a PWM output. This way you can adjust the luminosity while increasing battery life.

• Good idea in general and I'll definitely try it later, but at the moment, I'd like to avoid use of microcontrollers. If I'm right, blinking of the LEDs should be very hard to notice at high frequencies, right? – AndrejaKo Nov 12 '10 at 15:55
• Yes, but flashing, even at high frequencies, will decrease the amount of light generated. – RMAAlmeida Nov 12 '10 at 23:30

You need a buck DC-DC converter for highest efficiency. It has to be designed to produce the desired average current rather than a fixed average voltage.

The ideal is to design the product to have zero resistors - then you know that the power wasted as heat in resistors is zero. After that, efficiency is a matter of LED semiconductor physics - good luck with improving that!

• I'll look into that. – AndrejaKo Nov 12 '10 at 16:37

Series connected batteries add voltage but the capacity stays the same, more or less. Parallel connected batteries add capacity, if they are of the same voltage.

You could consider a boost circuit to suck the last joules out of your battery. Something like a MCP1640T would let you run the 3.6V LED's from a 1.5V battery. If you're clever and set the output voltage of the MCP1640T at the same voltage as the LED's you'll only need a small resistor, say around 1 to 10 ohms (to help with balancing the current between the LED's.) Unfortunately, the MCP1640T is a surface mount only part, which could pose problems for a one-time project.

• I'll take a look into that. Maybe I'll be able to find a similar circuit. – AndrejaKo Nov 12 '10 at 17:55
• Joule thief could work, but I think it only works for one or two LED's. Give it a go. – Thomas O Nov 12 '10 at 17:57

Those little T1-3/4 LEDs aren't very good for illumination. The high power ones are more efficient. Check out DIY forums on www.candlepowerforums.com for really good resources on LED lighting and flashlights.