# The two capacitors are in series but positive end of one plate is connected to positive end of the other

Like the title says, my task is to find the initial voltage across the terminals. The two capacitors are in Series with positive end of one plate connected to that of another.

The given information are:

$$\C_1\$$ = 12 microFarad, $$\V_1\$$ = 6 Volts, $$\C_2\$$ = 4 microFarad, $$\C_2\$$ = 2 Volts.

The circuit diagram is:

I have calculated the equivalent capacitance and I just need the total charge in the circuit to find the total or initial voltage using the equation,

Q = C*V

So, I first attempted to find $$\Q_1\$$ = $$\C_1\$$ * $$\V_1\$$ = 72 microCoulomb.

$$\Q_2\$$ = $$\C_2\$$ * $$\V_2\$$ = 8 microCoulomb.

I know that the positive charges accumulate on the positive end of the capacitor,

Hence, I am unsure whether $$\Q_T\$$ or Total Charge in the circuit = $$\Q_1\$$ + $$\Q_2\$$ or the difference between the two charges which is |$$\Q_1\$$ - $$\Q_2\$$|?

• That top capacitor is very dead. The symbol says it's a polarized capacitor, but it's got 6 V on it in the reverse direction; I don't think it's going to remain a capacitor for very long. Commented Jun 25, 2023 at 14:35
• It's an open circuit - no current is flowing and the charges on the capacitors have not equalized. Commented Jun 25, 2023 at 15:34