3
\$\begingroup\$

I've recently bought a soldering iron from China that buzzes audibly as it heats up the tip. I'm trying to understand the reason it makes the buzzing sound and mitigate it. What I observe is that as the tip heats up, there is an audible buzzing noise coming from the handle, the control board, and the power supply.

Here’s a video showing this problem, with the audio slightly amplified: https://youtu.be/Imbg9Skw5vQ

The working principle of the iron is quite simple (and this circuit is their exact implementation):

schematic

simulate this circuit – Schematic created using CircuitLab

It PWMs 24V into the tip and uses a PID control loop to measure the temperature and adjust the duty cycle as needed.

The iron (Aixun T3A) is rated for 200W, so the MOSFET switches hard when very significant current (~8A) is flowing. My current suspicion is that because the switching edges are too sharp, the significant change in magnetic field causes components in the PCB and the iron handle to vibrate.

So I would like to design a circuit that takes as input a 5V PWM like this:

enter image description here

and outputs a 24V high current PWM with softer edges (without any significant delay):

enter image description here

I'm not sure where to start with this. If I simply add a 10n capacitor across R2 for example, that messes up the timing of the PWM. Thanks for any help and guidance.

\$\endgroup\$
15
  • 1
    \$\begingroup\$ You will also need to consider the additional heat that will be generated and how to get rid of it. \$\endgroup\$
    – Gil
    Commented Sep 25, 2023 at 6:33
  • \$\begingroup\$ Yes, I'm aware that operating the mosfet in its linear region will produce some heat. That's perfectly fine. I have spare heatsinks \$\endgroup\$
    – darksky
    Commented Sep 25, 2023 at 7:20
  • \$\begingroup\$ I suspect this will solve your problems because the switching is already within the audible range. Although slowing down the rise/fall by adding some capacitors across the switching elements will tame some of the very high frequency harmonics, the fundamental (166 Hz) is still there. If fundamental is there then powerful harmonics are there as well. as the tip heats up, there is an audible buzzing noise coming from the handle, the control board, and the power supply. This could be the power supply as well i.e. it might be struggling to deliver the required power (192W times the duty cycle). \$\endgroup\$ Commented Sep 25, 2023 at 7:39
  • \$\begingroup\$ What frequency does it buzz at? The heat regulation frequency could be low but the power supply behind it may have the usual oscillation at the corner frequency of the output LC, usually in the 6-8 kHz region. This is notoriously common on cheap power supplies despite adding zero BOM cost to fix. \$\endgroup\$
    – winny
    Commented Sep 25, 2023 at 8:03
  • \$\begingroup\$ You can reduce higher harmonics this way, but likely not enough of them to reduce audibility. A microphone reading of the sound might be helpful. I assume it's an impulsive sound, but centered around what frequencies, is the question. \$\endgroup\$ Commented Sep 25, 2023 at 9:26

1 Answer 1

0
\$\begingroup\$

Relevant discussion from another community: https://www.eevblog.com/forum/reviews/any-opinions-on-the-aixun-t3a/

Buzzing isn't mentioned (or audible in the video), but it might be that build quality varies, or you have a clone or whatever.

Spectrogram

Here's the spectrogram (waterfall diagram from left to right) of audio from the video.

The blue and pink confetti is just background noise that can be ignored. Most harmonics are in red, with the 1.5k and 1.66k harmonics being most prominent. Probably because they're resonances of the handle or something. It's subtle, but the harmonics seem to swish around a bit, in the bracketed area, distinctive of PWM changing.

So yeah, it's fairly low harmonics (9th and 10th, and you'll still hear the rest; 20th+ would be more practical to filter electronically).

If you want purely electronic solutions, it could indeed be filtered. The impedance is low enough that a catch diode and series inductor could be added, and maybe filter cap too. Downside is, we need Fc << 166Hz. Say 40Hz to avoid cutting into the control loop bandwidth too much; this needs L = \$\frac{(3\,\Omega)}{2 \pi (40 \,\textrm{Hz})}\$ = 11mH, rated for up to 8A. Which will be a fairly large iron-core inductor. (A cap of \$\frac{1}{2 \pi (3\,\Omega) (40 \,\textrm{Hz})}\$ = 1.3mF can additionally be used.)

schematic

simulate this circuit – Schematic created using CircuitLab

which would look something like this. Note the diode must be placed adjacent to the switch transistor, and the inductor probably won't fit anywhere, it'll have to be hanging out the back of the base unit or something.

Smaller values may be reasonable (evidently around 500Hz would be the maximum to still get value, given the spectrum), but mind that they may distort the response (power output vs. duty cycle), which may upset the controller as well.

Ideally, the controller would run at much higher frequency (over 20kHz is easily done), with a compact LC filter inside the base. I have no idea if this is at all feasible to implement. You'd at least need the schematics and firmware, and a toolchain to reprogram it.

I mean, even more ideally, the thing just wouldn't buzz at all... Whether that's shoddy construction in the handle, base or both, or poor cabling, or a poor tip (try one of those famous JBC tips you mentioned?), who knows. Also, you might want to check wiring quality in general; with 8A peak flowing here, it would be very easy to skimp on wire size (don't forget they're fond of copper-clad aluminum or steel wire over there..!), not to mention the mains wiring and especially ground connection may be woefully inadequate (i.e., shop for a proper UL-rated unit).

\$\endgroup\$
2
  • \$\begingroup\$ Really interesting to see only the 9th harmonic is audible. I wonder if that massive LC network needs some damping? \$\endgroup\$
    – darksky
    Commented Sep 25, 2023 at 15:58
  • \$\begingroup\$ It does. Fortunately the load is very well defined! \$\endgroup\$ Commented Sep 25, 2023 at 16:14

Not the answer you're looking for? Browse other questions tagged or ask your own question.