I tried buying a cheap LED power supply ALIDOVE BRAND. I checked the voltage without/with Arduino and the LED matrix connected.
It's always 5.5 volts but it's working in its intended purpose - a clock (tried it only for 4 sec for fear of destroying the LED). Will it not damage the LED WS2812B matrix?
I'm asking this question because of conflicting info on the net and I cant find a reliable info.

  • \$\begingroup\$ What does the datasheet for the WS2812B say its input voltage range is? \$\endgroup\$
    – Aaron
    Nov 16, 2023 at 22:41
  • \$\begingroup\$ I tried buying yeah that never succeed. \$\endgroup\$
    – MiNiMe
    Nov 16, 2023 at 22:42
  • \$\begingroup\$ You need to find the spec for your LED matrix. Some are only rated up to 5.3 V. It isn't that hard to make a power supply with +/-5% tolerance. I suspect that they set the voltage a little high intentionally to satisfy inexperienced customers who tend to undersize their wires. \$\endgroup\$
    – Mattman944
    Nov 16, 2023 at 22:47
  • \$\begingroup\$ Only the cheap one in aliexpress, so theres little info there. Read the reviews on alitove power supply , about voltage not even 5 volts previously so maybe they make it so much higher.. \$\endgroup\$ Nov 16, 2023 at 23:20
  • \$\begingroup\$ you can put a schottkey diode in series with VCC to shave off about 350mv. it should be fine though, even if cheap crap. Are you sure the power supply is at 5.5v under load? Many are a tad higher open-circuit than when actually doing stuff. \$\endgroup\$
    – dandavis
    Nov 16, 2023 at 23:35

1 Answer 1


The spec sheet states "Electrical Characteristics(T A =-20~+70 ℃ ,V DD =4.5~5.5V,V SS =0V, unless otherwise specified).

The operating voltage limit is given as 5.3 V, but it's unlikely damage was done by an excess 0.2 VDC.

  • \$\begingroup\$ tried other 5volt power supply i have, they gave 5.3 volts W/O load so maybe 5 volts fixed is impossible.Anyway thanks.. \$\endgroup\$ Nov 16, 2023 at 23:23

Not the answer you're looking for? Browse other questions tagged or ask your own question.