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I have 4 different inputs In0, In1, In2 & In3. Each input is 4-bit, so there are total of 16 inputs. There are two selector inputs S0 & S1. And there is a 4-Bit Out. i.e. depending on the state of the S0 & S1, for ex. "00", 4-Bit In0 will be assigned to 4-Bit Out. I need to do this using a Mux/Demux switch but i could not understand how Mux/Demux switch can be used. Any guide will be greatly appreciated.

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  • \$\begingroup\$ Can you do the same for 4-1 mux (that is the same, but for 1-bit inputs/outputs)? \$\endgroup\$
    – Eugene Sh.
    Dec 7, 2023 at 15:21
  • \$\begingroup\$ @EugeneSh. If I use 4x1 mux, then only one bit of the required 4 bit will be taken. I need the remaining three bits as well as they are connected to another decoder. \$\endgroup\$
    – Zzz
    Dec 7, 2023 at 15:59
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    \$\begingroup\$ Again, can you implement it? If you can, you simply parallelize four of your implementations interconnecting the Select lines. \$\endgroup\$
    – Eugene Sh.
    Dec 7, 2023 at 16:17
  • \$\begingroup\$ I am having difficulty in deriving the truth table, can you point to any references, I could not find any. \$\endgroup\$
    – Zzz
    Dec 7, 2023 at 16:29
  • \$\begingroup\$ @Zzz difficulty in deriving the truth table ... do you understand how a MUX functions? \$\endgroup\$
    – jsotola
    Dec 7, 2023 at 16:45

1 Answer 1

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Typical 4:1 muxes (there are many devices, with "4052" in their name) have two channels:

4052 mux
(source)

Use one channel for each bit, i.e., you need two chips.

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