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The circuit given in the following Figure is a voltage regulator which is used to supply a constant voltage. It has the following properties: Vin = 20V, Rs = 1 kΩ, R1 = 200 Ω, R2 = 800 Ω, R3 = 2 KΩ, RL = 100 Ω, Vz = 5.6V, βdc = 100.

Vin = 20V Rs = 1kΩ R1 = 200Ω R2 = 800Ω R3 = 2kΩ Rl = 200Ω Vz = 5.6V βdc = 100

Vf = 0.7V (?) Vout = 5.6V (?) Ic2 = ? Ib2 = ? Ic1 = ? Iz = ? PQ2 = ? Pz = ? RL = ?

I am having immense trouble with this one. So far, Vz = Vout when using a Zener diode? So 5.6v? Vf = 0.7v? (Threshold voltage of a diode?)

Any help would be appreciated!

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    \$\begingroup\$ Have you tried to simulate the circuit, poke around and see what values affects which parameters? \$\endgroup\$
    – winny
    Commented Dec 12, 2023 at 9:52
  • \$\begingroup\$ I have replicated the circuit and placed current probes but I am getting 0 on all of them. I'm out of my depth. \$\endgroup\$ Commented Dec 14, 2023 at 19:44
  • \$\begingroup\$ Please share a screenshot. This problem should be entirely solvable in SPICE. \$\endgroup\$
    – winny
    Commented Dec 14, 2023 at 20:08

1 Answer 1

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Any help would be appreciated!

Maybe you should think along these lines; ask yourself what voltage has to appear on the base of Q1 (with respect to ground) such that base current begins to flow. I mention this because, when Q1's base current starts to flow, you reach the onset of the circuit turning into a voltage regulator.

Then, once you have established this value, you can calculate what the output voltage must be. This requires recognizing that the R1 and R2 form a potential divider from the output to Q1's base.

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  • \$\begingroup\$ 5.6 - 0.7? = vF? \$\endgroup\$ Commented Dec 14, 2023 at 19:46
  • \$\begingroup\$ voltage divider circuit? \$\endgroup\$ Commented Dec 14, 2023 at 19:46
  • \$\begingroup\$ No. 5.6 - 0.7 = Vout? \$\endgroup\$ Commented Dec 14, 2023 at 20:07
  • \$\begingroup\$ @NonComposMentis I don't understand any of your three comments. If we are done here, please take note of this: What should I do when someone answers my question. If you are still confused about something then leave a comment to request further clarification. \$\endgroup\$
    – Andy aka
    Commented Dec 17, 2023 at 17:06

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