enter image description here

I know the answer is Vs=Vo, by simulation. BUT I don't know why. In steady state inductor is gonna be short. And Vs is parallel with Vin and Vout. Can you tell me what is wrong?

  • \$\begingroup\$ I recommend you take a look at the tutorial I built on switching converters. It will show you the switching steps for this boost converter. \$\endgroup\$ Mar 30 at 8:35

1 Answer 1


The converter you drew is a boost converter, not a buck converter. I don't know why you shorted the inductor in the second phase. In that phase, the inductor is not shorted, and the voltage across the switch is \$V_O\$ (assuming an ideal diode with zero voltage drop). enter image description here Image taken from Wikipedia: Boost converter.

  • \$\begingroup\$ I'm dumb student... I thought Inductor gonna be short ...Thank you \$\endgroup\$
    – cocoromina
    Mar 30 at 7:19
  • \$\begingroup\$ @cocoromina I think I now understood your sentence regarding the inductor being shorted in steady state. That would be true if the converter stayed in the second phase forever, but that isn't the case as it is a switching converter that alternates between phase 1 and phase 2. \$\endgroup\$
    – internet
    Mar 30 at 7:23

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