I have this circuit where I have to find the Thevenin equivalent. How do I solve this problem by nodal analysis?
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\$\begingroup\$ Welcome! Is this homework? What have you tried so far? \$\endgroup\$– winnyCommented Apr 8 at 9:04
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\$\begingroup\$ No this is not a homework problem.I have tried solving this problem by Nodal analysis. But the answer seems incorrect . I wonder whether Nodal analysis applicable to this circuit. \$\endgroup\$– VikasCommented Apr 8 at 9:06
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2\$\begingroup\$ Please show your attempt and we’ll help you from there. \$\endgroup\$– winnyCommented Apr 8 at 9:13
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\$\begingroup\$ @Vikas Looks like I can see that this came from "MADE EASY Publications". So are you self-learning? In any case, for nodal -- if that's your requirement here -- you will want to assign a ground node. My recommendation is to assign that to the bottom wire in your diagram. Then you place a switchable current source at the output that can be set to 1 A or to 0 A. And you will have a total of three KCL node equations. Then it is directly solvable for the Thevenin equivalent using nodal analysis. Let me know the source for this problem and I may write. \$\endgroup\$– periblepsisCommented Apr 8 at 10:05
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\$\begingroup\$ @Vikas And yes, nodal analysis is entirely applicable to this problem. And if you are using MADE EASY pubs, then I do understand why you would need to use, specifically, nodal analysis to solve it. They are part of a set of publishers creating preparation materials touching upon a wide variety of areas where you must demonstrate proficiency. So I get it, if that's the source. Again, let me know if that's the source and your goals. \$\endgroup\$– periblepsisCommented Apr 8 at 10:13
3 Answers
From a comment by the op: -
I wonder whether Nodal analysis applicable to this circuit.
It is applicable in that you can apply nodal analysis to the circuit but, this site is about circuits and understanding circuits and transforming circuits so, I would go down the route of source transformation to solve this. Here are a few simple pictorial steps that should help you get to the answer you want: -
You should be able to see that the Thevenin voltage is 22 volts and, the Thevenin resistance is 9 Ω (with hardly any math involved at all).
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\$\begingroup\$ Thanks @Andy aka ,I realised my mistake. I tried nodal analysis without the source transformation. \$\endgroup\$– VikasCommented Apr 9 at 1:49
Yes I am self learning.The question asks for Maximum power for the load resistance.So,using maximum power transfer theorem we have to find the load resistance which should be equal to thevenins resistance
Hmm. But your title says:
How to solve this question by nodal analysis?
So I will take it that you understand already that the Thevenin impedance must be matched by the load. That's good. I'm glad you already understand that fact.
Here's an updated diagram for nodal analysis:
From this, we can form the following nodal equations:
$$\begin{align*} \frac{V_1}{R_1}+\frac{V_1}{R_2}+\frac{V_1}{R_3} &=\frac{V_0}{R_1}+\frac{V_2}{R_3} \\\\ \frac{V_2}{R_3}+\frac{V_2}{R_4}&=\frac{V_1}{R_3}+\frac{V_3}{R_4}+I_0 \\\\ \frac{V_3}{R_4}&=\frac{V_2}{R_4}+I_1 \end{align*}$$
We will use two values for an injected current, \$I_1\$: at \$0\:\text{A}\$ and \$1 \:\text{A}\$:
EQ1 = Eq( v1/r1 + v1/r2 + v1/r3, v0/r1 + v2/r3 )
EQ2 = Eq( v2/r3 + v2/r4, v1/r3 + v3/r4 + i0 )
EQ3 = Eq( v3/r4, i1 + v2/r4 )
solve([ EQ1, EQ2, EQ3 ], [ v1, v2, v3 ])[v3].subs(
{ v0:12, i0:2, r1:6, r2:12, r3:3, r4:2, i1:0 })
22
solve([ EQ1, EQ2, EQ3 ], [ v1, v2, v3 ])[v3].subs(
{ v0:12, i0:2, r1:6, r2:12, r3:3, r4:2, i1:1 })
31
From the above, you can see that the unloaded voltage is \$22\:\text{V}\$ and that after injecting \$1\:\text{A}\$ that the voltage moves to \$31\:\text{V}\$. So this says that the Thevenin impedance is \$9\:\Omega\$.
So that is the load impedance needed to maximize the power delivery into the load.
The above uses nodal analysis to reach this result, as requested.
As proof, here's the result from LTspice:
You can readily see that the peak power in the load occurs when the load impedance is \$9\:\Omega\$.