Calculating Core Loss Coefficient (Kfe) for Ferrite Materials

I'm having trouble calculating the core loss coefficient Kfe for ferrite materials. I'm referencing Chapter 15 of "Fundamentals of Power Electronics" by Robert W. Erickson and Dragan Maksimović.

The textbook defines Kfe in units of W cm-3 T, where β is the core loss exponent. For modern ferrite materials, β is between 2.6 and 2.8. In the Cuk converter example (15.3.1), a ferrite pot core with Kfe = 24.7 W cm-3 T is used, while in example 15.3.2, Kfe = 7.6 W cm-3 Tβ.

I attempted to calculate Kfe using Steinmetz's equation with datasheet parameters from Ferroxcube's "Soft Ferrites and Accessories" for materials 3C91 and 3C93:

For 3C91 (100 kHz, β = 2.7, Bpeak = 200 mT, Pv = 300 kW m-3):

$$K_{fe} = (0.3\ \mathrm{W\,cm^{-3}}) / ((0.2T)^{2.7}) \approx 23.13\ \mathrm{W\,cm^{-3}\,T^{-\beta}}$$

For 3C93 (100 kHz, β = 2.7, Bpeak = 100 mT, Pv = 50 kW m-3):

$$K_{fe} = (0.05\ \mathrm{W\,cm^{-3}}) / ((0.1T)^{2.7}) \approx 25.06\ \mathrm{W\,cm^{-3}\,T^{-\beta}}$$

Questions:

1. Are my calculations correct, or am I missing something?
2. Is there a better way to compute the core loss coefficient (Kfe) for ferrite materials?

The table is filled with formula e.g. C21 = =$B$12*($B21^$B$13+$B$15*$B21^$B$14)*C$19^$B\$16 repeated by row and col, and B6 = =B3*B12*((B4*1000)^B13+B15*(B4*1000)^B14)*B5^B16/1000000*1000^B16. Basically, the expected formula, accounting for unit multipliers, and applied across rows/cols.