I'm experimenting with a power supply circuit to bring 24VAC down to 5VDC. I have an L7805CV, but rectified (a bridge) and smoothed (a 33μF electrolytic), the input is still \$40V_{peak}\$, which is more than the max input voltage the regulator can take. Looking at the regulator's datasheet, it suggests the following "High Input Voltage Circuit", which notes "\$V_{in} = V_i - (V_Z + V_{BE})\$", but doesn't offer any guidance on Q1 or R1:


simulate this circuit – Schematic created using CircuitLab

I have a 27V (½W) zener (NTE 1N5033A), but either

  1. i'm misunderstanding something,
  2. my diode is mislabeled, or
  3. i've damaged it,

because when i orient it as indicated, with the striped cathode end toward \$V_i\$, the voltage at \$V_{in}\$ is the full 40V minus approx. 2 diode-drops and the voltage across the zener is only about 0.7V. (Note that at this point, i have a 33k resistor to ground in place of the 7805 so i don't damage it until i get the limiter right.)

My multimeter's diode setting seems to indicate that the markings on the diode are backward. That is, it behaves opposite the way my other diodes do.

If i install it the other way around, the voltage at \$V_{in}\$ is only about 12V, which is approximately 40V - 27V - a reasonable \$V_{BE}\$.

It is possible that it's really just marked wrong? I made some mistakes wiring it up the first time and something let out a wisp of smoke before i cut the power, but i wasn't able to figure out which component, and everything i've been able to test measures okay. Could overcurrent have somehow magically reversed this diode?

I added some bits to make it simulate better: https://www.circuitlab.com/circuit/9b6y3x/weird-zener-limited-7805/

Here's a picture of the diode in situ, along with its packaging:

enter image description here

Here's a picture of a 7.5V zener from the same manufacturer with the same diagram on the back of the package:

enter image description here

The second Zener's polarity is what you'd expect; only the 27V zener is weird.

  • \$\begingroup\$ Some manufacturers sell the parts under a different name than "zener diode", which justifies (in their eyes) to move the band to the anode. I've read an article on it a while ago, but can't find it right now and can't remember the alternative diode name for them. Anyways always check a zener's polarity. \$\endgroup\$
    – jippie
    Jun 3, 2013 at 6:41
  • \$\begingroup\$ @jippie i will from now on! :) \$\endgroup\$ Jun 3, 2013 at 7:12
  • \$\begingroup\$ Overcurrent cannot magically 'reverse' a zener, at least not in my experience. It can and will let out that magic zener barrier smoke that makes the device work, however. \$\endgroup\$ Jun 3, 2013 at 12:35
  • 3
    \$\begingroup\$ Just for future reference, the zener effect is a very specific effect and in Si it renders a breakdown voltage ~ 5.6 V. Higher voltages are typically avalanche diodes, which is a different mechanism but the term "zener" has erroneously come to be applied to both types. The distinction is important when you are using the Temperature coefficient of voltage (which is different between the two processes). Some voltage ranges of these breakdown diodes have contributions from both effects so it can be confusing. \$\endgroup\$ Jun 3, 2013 at 15:26
  • \$\begingroup\$ too late too reply now, but the breadboard has this zener diode inserted the wrong way :-). Cathode with white strip has to be at the big capacitor side, on the left! \$\endgroup\$
    – Zman
    Jun 24, 2018 at 2:53

2 Answers 2


The behavior you describe reproduces in the simulated circuit exactly. If we configure the Zener to a 25 reverse voltage and have it in the circuit the right way, Q1 drops around 25V. If we reverse the Zener, we get approximately two junction drops, as you found empirically. So it looks like you have the right circuit, and that the Zener is marked wrong. The stripe on the diode should correspond to the cathode bar on the schematic.

A long-standing rumor is that NTE buys other manufacturers' semiconductors and stick their own name and their own NTE-specific part numbers on them, possibly after testing the parts to figure out what they are. Maybe your diode came from a batch that ended up as NTE because they were marked backwards.

  • \$\begingroup\$ Ha! That would be amusing. \$\endgroup\$ Jun 3, 2013 at 6:44

The black ring on the Zener should typically be the same as the "bar" on the schematic. However, weird manufacturers may do weird things. Have you checked the markings on the Zener to the data sheet? What brand and model Zener is it?

Overvolting a Zener and letting out the magic smoke will typically just make it short out, it won't "reverse" the direction of it.

Note that the circuit shown is basically just building another (simpler) voltage regulator to burn off the voltage seen by the Zener. If you want to go from 40V to 5V drawing more than a few milliamps, you probably want to use a switching buck converter, rather than a linear regulator, to avoid generating 8x as much heat in regulation as you actually put out as useful regulated current/voltage.

  • \$\begingroup\$ Thanks! I added more info and pictures (though i could neither inline the images nor even make them proper links due to low reputation). Re: buck converters, that was what i was going to play with next, but i'm trying to baby-step my way up the complexity ladder :) The only reason i'm even using 24VAC is that i'm powering lawn-sprinkler solenoids and thought having two transformers would be silly/bulky. Really, though, a 7.5VAC transformer would make a lot less heat. Anyway, this reversed zener was bizarre enough that i wanted to ask for help online. \$\endgroup\$ Jun 3, 2013 at 6:24

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.