# Caculate the base/ emitter current of PNP transistor

Excuse me, I'm having trouble with my Semiconductor-Experiment Exercise. The transistor code (if necessary) is A1015.

Here is the question: Instead of connecting load (Resistor & LED) to Collector of PNP, we connect it to Emitter like the image above. Can the transistor reach saturation mode?

I just have some basic ideas, the transistor can reach saturation mode if the V_ce is low enough (for below 1V) and the Vce = Vcc-Vdiode-Ic*R1

So, can you figure out how to caculate the Vce and the Base current? Thank you so much.

• "Vce = Vcc-Vdiode-Ic*R1" assumes that the transistor has infinite gain and the base current is zero. So you need a better equation. Commented May 27 at 8:35
• @Finbarr thank you very much, but can you give me a hint for the equation please? Commented May 27 at 8:39
• Collector current = base current + emitter current Commented May 27 at 8:40
• @Finbarr So it will be: ie = ic + ib = ic + Vb/10k right. And is Vb = 0.7V sir Commented May 27 at 8:44
• Sorry, it's PNP so emitter current = base current + collector current. And 0.7V is the voltage between emitter and base, not the actual voltage on the base. Commented May 27 at 8:48