I have an AQZ204 AC/DC type solid state relay AQZA204 datasheet
I'm using 31.5 volt DC supply, with a series 4.7k Ohm Resistor to the input LED of the relay.
The data sheet is a little confusing to me, it saids the LED max dropout voltage is 1.5V so I calculated around 6.38mA forward current for the LED:
31.5VDC - 1.5Leddrop = 30VDC/4700 = 6.38mA
I'm confused by the IFon current being 3mA max?
Basically I want to calculate the minimum supply voltage required to turn the relay on
and the minimum supply voltage required to turn the relay off
So I can test the relays to see if they are in spec.