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I have a circuit in which I have two different AC voltage sources (both 230 V) and a common load.

The aim of the circuit is that voltage source 1 is connected to the load; if voltage source 2 is also connected, voltage source 1 should be disconnected from the circuit.

I would only switch the life conductors with the semiconductors (optocouplers).

Briefly about me I have a BSc in automotive engineering, so I have some basic knowledge but not enough to realise the project by myself.

I have now made a schematic and would be happy if you could give me some feedback before I order the components. Especially whether it works at all and whether I still need capacitors or similar as a filter because 230 V AC voltage is at 50 Hz.

I am also open to try completely different approaches.

Please find the technical datasheets (TDS) and the schematic

TDS SSR

TDS Optocoupler

TDS Inverter

enter image description here

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    \$\begingroup\$ First, the inverter Vss pin is not connected. \$\endgroup\$
    – AnalogKid
    Commented Aug 8 at 16:29
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    \$\begingroup\$ Ignoring the details of your circuit for now, it's pretty easy to have both thyristor SSRs to turn on at once (for example, from a transient) and blow them both up. A mechanical relay interlock (you can do the actual switching with semiconductors after the relay transfers) or MOSFET type SSRs (with suitable dead time) may be a better approach. \$\endgroup\$ Commented Aug 8 at 16:30
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    \$\begingroup\$ Why are you wanting to design a transfer function yourself instead of buying a COTS transfer switch? \$\endgroup\$ Commented Aug 9 at 1:57
  • \$\begingroup\$ @ThreePhaseEel Thank you very much for your comment. I didn't expect there to be such a thing. I will use something like this for the first version of my project until I really understand what I am doing. \$\endgroup\$
    – AlMo93
    Commented Aug 9 at 8:16
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    \$\begingroup\$ @SamGibson Sorry, I now understand the principle and will stick to it in future. \$\endgroup\$
    – AlMo93
    Commented Aug 9 at 12:43

3 Answers 3

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That's not going to work. Redraw your circuit using only V1, V2, X1 and replace the SSRs with switches.

Now figure out what happens when SSR1 is closed, SSR2 is closed and both are closed.

schematic

simulate this circuit – Schematic created using CircuitLab

Figure 1. Equivalent circuit for analysis.

Now, what is the optoisolator doing in your circuit?

schematic

simulate this circuit

Figure 2. A simplified circuit that doesn't switch neutrals and includes protection devices.

  • There is no need to switch neutrals as in your two diagrams. It complicates things, leads to errors and makes troubleshooting more difficult.
  • I'm not recommending this circuit because it doesn't address synchronisation, interlocking or switchover delay.
  • I highly recommend installation of fuses or MCBs on both supplies.
  • SSRs are probably more likely to fail short-circuit than a relay contact will. (I don't have any numbers to back this up but have used both for > 40 years in industry.)
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  • \$\begingroup\$ I didn't think I could leave the neutral conductors together, but of course they are neutral. I will now also install the MCBs to prevent further risks. What kind of circuit would you recommend? I think the synchronisation in particular will be unnecessarily complex, but I think a circuit that delays the switching makes sense. What do you mean by interlocking? \$\endgroup\$
    – AlMo93
    Commented Aug 9 at 12:52
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Are the two AC sources in perfect phase alignment? If not, two things.

a) the load might not like an instantaneous voltage change of up to 750 V.

b) the two AC sources might not like being connected directly together for a few milliseconds.

Many (most?) solid state relays have a TRIAC as the switching device. This is a solid state device that can be turned on at any point in the AC cycle. However (the bad part), when you remove the gate signal in the middle of a cycle, the TRIAC stays on until the next zero-crossing of the AC waveform. If the two AC sources are not in perfect phase alignment, this can cause a huge cross-conduction current between the two sources as one TRIAC comes on before the other one turns off.

One solution for this is to create a dead band, a short time delay between when one AC source is turned off and the other is turned on.

UPDATE:

Based on new information, a single component that will do what you want is a DPDT relay powered by AC source #2. This will disconnect AC #1 from the load and connect AC2 only when AC2 voltage value is above the actuation voltage of the relay. Note that this must be a double-pole relay because the two neutrals are not phase-aligned.

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A relay or a contactor should suffice.

enter image description here

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  • \$\begingroup\$ This seems so simple and straightforward. I love it! Now for my understanding I don't need capacitors or anything to prevent sparking while the relay is switching a large current (max 20A) is flowing? \$\endgroup\$
    – AlMo93
    Commented Aug 9 at 12:58
  • \$\begingroup\$ Thank you! All that you require is a relay/contactor having a contact rating > 20 A ~ resistive or > 20 A ~ inductive depending on the load being resistive or inductive. \$\endgroup\$
    – vu2nan
    Commented Aug 14 at 4:41

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