3
\$\begingroup\$

Lets say I have this circuit:

schematic

simulate this circuit – Schematic created using CircuitLab

I think if I apply a 0 to the base of Q1, I'll develop something like 4.3V at the collector of Q1, right? In that case with the Base of Q2 sitting at 4.3V which is higher than its collector voltage of 1.8V to 3.2V, what will be Q2's behavior. Will current flow through R4 sourced from V1?

\$\endgroup\$
5
\$\begingroup\$

With 0 on Q1's base, Q1 will saturate to probably within 100mV of the 5V rail i.e about 4.9V on the collector. If it were an NPN emitter follower and you applied 5V to the base, the emitter would be at 4.3V - maybe that's where you are having a minor bit of confusion?

With Q2's base sitting at 4.9V and its collector being at (say) 3.3V you'll have a heavily forward biased base-collector diode (un-natural operations) and may indeed damage Q2 due to excessive current flow.

Iif you had (say) a 10k resistor in series with Q2's base this would protect the device and you would see a voltage of nearly 3.3V on the emitter because Q2 would be saturated-on.

| improve this answer | |
\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.