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When distance between the plates is increased, what will happen to the value of the capacitance. (a) Increases (b) decreases

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    \$\begingroup\$ Before coming here what have you done to find your answer? \$\endgroup\$
    – Andy aka
    Jul 7, 2013 at 10:27
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    \$\begingroup\$ Do your own homework. \$\endgroup\$ Jul 7, 2013 at 12:13

1 Answer 1

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From Wikipedia:

In a parallel plate capacitor, capacitance is directly proportional to the surface area of the conductor plates and inversely proportional to the separation distance between the plates.

parallel plate capacitance formula

where C is the capacitance; A is the area of overlap of the two plates; εr is the relative static permittivity (sometimes called the dielectric constant) of the material between the plates (for a vacuum, εr = 1); ε0 is the electric constant (ε0 ≈ 8.854×10−12 F m–1); and d is the separation between the plates.

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