I want to design a circuit having output voltage of 3.3 V and 30mA current. As I am newbie in the electronics field, I see lots of circuit using buck topology, using IC's and using transformers.
Now as I heard something great in my BOOK i.e. current mirror configuration using BJT. As far as explained in my book, it is a circuit consisting of two matching transistors with the collector of one connected to the bases of both,thus producing the same collector current in each transistor.
Now in order to get the collector current in mA, only a small amount of uA current is required. By providing a little amount of base current can I get the sufficient amount of current from the collector end which s furthur used in my application??
If using this (current mirror configuration) with a capacitor power supply(using 0.15uF cap which gives upto 11mA currnt) then its easy to get a small amount of current in uA which is furthur supplied to the base terminal.
If not then what is the reason as I really stuck at that place.I also searched it on internet but didn't get a good response.