The full wave bridge rectifier shown provides a DC output voltage of +/- 15 volts on which 1V peak to peak ripple is allowed. The supply should be capable of providing 1A DC current to its load resistor R find:
- The required rms voltage that must apear across the transformer
- The required value of C and R
- The average DC current
- The peak DC current through the diode
I don't get what is the relation between the DC output voltage and Vs in another word how can I get benefit from +/- 15 volt to calculate Vs?
Also (Vpeak = Vo + Vr) according to this law can I consider the Vo as 15 and Vr as 1? Is the ripple voltage value in this law for peak to peak or I have to regard it as 0.5? And what about the current of 1A, is it the average DC current?