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I have a circuit that has the emitter side of a NPN tied to the emitter side of PNP. I need to find the output voltage on the emitter. Base voltage is a sine wave. Can someone help me understand what this kind of configuration is used for? And how should I go about to calculate the power dissipated by the resistor?

enter image description here

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    \$\begingroup\$ you're going to have to at least draw a schematic and give transistor numbers... \$\endgroup\$ – placeholder Oct 27 '13 at 15:08
  • \$\begingroup\$ Sorry I didn't upload a schematic at the beginning. \$\endgroup\$ – Kieran Bingw Oct 27 '13 at 19:21
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You mean like this?

enter image description here

This is a push-pull emitter follower. The ideal case: the output equals the input. The practical case: there is a Vbe (~0.7V) crossover distortion which causes a deadband for input signals around 0V.

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  • \$\begingroup\$ Perfect. This definitely helps \$\endgroup\$ – Kieran Bingw Oct 27 '13 at 19:18

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