I just found out that some capacitors hardly leak whereas other types of capacitors leak a lot of current through the dielectric. I’ve looked at Wikipedia and found several links (Leakage and Capacitor plague) which does not really described the current leakage (to the best of my understanding). The capacitors we used worked well and were not damaged in any way that I could see.


  1. What causes capacitors to leak?

  2. Which type of capacitor leak more: electrolytic or non- electrolytic capacitors? Does the direction of the electrolytic capacitor matter for current leak?

  3. From my experience, does one get more leakage current if the electrolytic capacitors is reversed? If so why?

  • 1
    \$\begingroup\$ leak charge or leak dielectric? \$\endgroup\$ Nov 5, 2013 at 21:00
  • \$\begingroup\$ @GustavoLitovsky: I believe what I am asking (I am not clear on this) is there is a current leak through the dielectric material. So it would be "leak charge." \$\endgroup\$
    – Jesus
    Nov 5, 2013 at 21:05
  • \$\begingroup\$ I think you have them reversed. Electrolytic caps have larger capacity it may take a bit longer before you notice on the test bench, but relatively they leak more. \$\endgroup\$
    – jippie
    Nov 5, 2013 at 21:22
  • 2
    \$\begingroup\$ Electrolytics leak current more than non-electrolytic types so maybe you need to re-phrase your question after doing a bit of research on google because although you knew you might have this the wrong way round you need to understand what a capacitor is before asking this question. I mean, do you know what a capacitor is? There's nothing on your profile to give a clue about what you know so good answers may be wasted on you. I'm not being nasty I'm just pointing out that you probably need to do some research first. \$\endgroup\$
    – Andy aka
    Nov 5, 2013 at 21:24
  • \$\begingroup\$ @jippie: I was not sure which capacitor it was - thanks. In my physics class, they had a low-leak electrolytic capacitor so I assumed that this was the case. \$\endgroup\$
    – Jesus
    Nov 5, 2013 at 21:26

1 Answer 1


The short answer is: insulator thickness. But that probably will not suffice as an actual answer.

It is helpful to understand how capacitors are made. All capacitors we frequently use in electronics are essentially flat plates with insulation in between them. The plates are some kind of metal and the insulation is often plastic or ceramic material. We usually call capacitors by one of these materials: aluminum electrolytic capacitors are literally aluminum foil with a liquid electrolyte in between. Ceramic multilayer capacitors have lots of layers of conductor and ceramic slurry in between them, and tantalum capacitors have the element Ta as its conductor (plate).

The key to making a capacitor is getting two plates with the largest possible area as close as possible to each other without them conducting to each other. You can imagine that this is pretty hard; mechanically it is very hard to get two surfaces exactly parallel and have only in the order of microns or hundreds of nanometers in between them, which is what you need for the thousands or tens of thousands of microfarads, somtimes even tens to thousands of farads we use in electronics today. So an insulator is used in between two conductive plates, but in order to guarantee that the insulator is mechanically strong enough to survive manufacturing and useful life, it usually needs to be fairly thick - tens to hundreds of microns is typical for for instance MKP capacitors. This increases the distance between the plates to far beyond what is necessary for electrical insulation, only to serve a mechanical purpose.

So, in aluminum electrolytic capacitors (and all electrolytic capacitors in fact), a trick is used to reduce the plate distance without actually putting the plates in very close proximity to each other. What they do: - One plate is oxidized to form a very thin, well-controlled insulating layer on its surface which can be as little as tens of nanometers thick - The other plate is left with a conductive surface - A sponge-like, fairly thick mechanical divider is placed in between the plates, but it is drenched in an electrically conductive liquid called the electrolyte.

This electrolyte effectively moves the plates much closer together, as if only the oxide layer on the first plate is the actual distance between them. This allows for a much, much higher capacitance in electrolytic capacitors than other methods of constructing capacitors.

Alright, with this kind of information under our belt we can see why leakage is more pronounced in electrolytic capacitors. Leakage is caused by four major mechanisms:

  • Electrical conductivity through the insulator
  • insulation breakages
  • Electrolyte deionization
  • Electron tunneling

The first one is simple: even the best insulator still conducts a little bit of electricity. The fact is that inside a large-value capacitor, there is a ton of surface area of the oxide layer, and even with a very low conductivity, if you have a lot of surface area the amount of leakage will be significant. This is especially significant for special super high-capacity electrolytics, where the aluminum foil inside is not just a coiled flat piece of foil, but the manufacturer has etched patterns into the foil to dramatically increase the amount of surface area of the aluminum.

The second one is also simple. Electrolytics are made by winding up coil and electrolyte 'sponge' together, and during this winding process mechanical stress and material imperfections cause tiny microfractures in the oxide surface. This allows electrons to directly flow between the plates, i.e. leakage current.

Then there is electrolyte dielectric effects. The electric field between the plates does cause some dielectric effects in the electrolyte, which change with the voltage (strength of electric field) over the plates. This means that usually at higher voltages, there is disproportionally more leakage current but at the same time higher ESR because the electrolyte ions are less free to move and are pulled in one direction by the electric field.

Lastly I should mention electron tunneling over very thin oxide layers. This is not an issue for run-of-the-mill electrolytics, but especially ultracapacitors suffer from this phenomenon a lot. Quantum-mechanically, electrons can be regarded not as a single point of charge, but a probability density of the electron being somewhere (wave-like behaviour of elementary particles). The probability of an electron being on the conductor is very high, and as you move further away from the conductor the probability of the electron being there decreases until it becomes essentially zero a few nanometers away. When an oxide layer is extremely thin, the probability of an electron that sits on the conductor to be on the other side of the oxide layer is nonzero, i.e. there is a probability that the electron 'jumps' over the oxide layer. This is called quantum tunneling and starts playing a role in leakage current when you approach nanometer-scale insulators.

So, to get back to your question: even though it may seem like it, by far the most important reason that electrolytic capacitors seem to leak more is that they simply have more capacitance and, by association, larger surface areas and thinner insulators which both contribute to higher leakage. If you would make any other construction of capacitor with the same specifications, they will exhibit fairly similar leakage characteristics. Yes, there are some unique reasons why electrolytics fare a little bit worse on the leakage side, but this is not something that puts the technology in a completely different order of magnitude of leakage.

  • \$\begingroup\$ Fantastic answer! Of the four mechanisms you listed, I expected the first two and learned a lot from your explanation of electrolyte deionization. This sent me back to Wikipedia to look at electrolytic capacitors, which made a lot more sense reading it a second time. However, I was surprised most by the tunneling (I am currently in an advance quantum class) through the oxide layer and loved reading this. \$\endgroup\$
    – Jesus
    Nov 6, 2013 at 12:09

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.