Electronics theory newbie here (please be gentle):
So I have an old guitar amp that had a crackly volume control. It also had an annoying habit of going from no volume to "too loud" with the slightest twist past 0 (let's assume this was by design and not a fault of the pot for now).
I opened it up and it was a 10kΩ type B pot (linear taper from what I've read).
I went ahead and replaced it with a 5kΩ type B pot, my logic was that I could get finer grain control when twisting past 0, as a given rotation on a 5kΩ pot would change the ohms by a half the amount of a linear 10kΩ pot. The crackle went and I did indeed get finer grain control.
Now I'm puzzled why this worked in the first place? My basic understanding was that originally, whilst the potentiometer was dialed into zero, it would have had a 10kΩ resistance, which kept the volume so low to be inaudible, as the pot swept towards 0Ω, the signal faced less resistance and the volume increased, however this 'theory' cant be correct as the 5kΩ pot when dialed to 0 was also inaudible. If my 'theory' was correct then the (linear) 5kΩ pot should of had the same volume as the (linear) 10kΩ when dialed half way, which was VERY LOUD, it didn't!
I can only really think of of the following as to why this is happening:
The circuit is wired to "sweep backwards" i.e. 0Ω (on the other terminal) would be inaudible, turning the dial to 1 would INCREASE the ohms and this somehow INCREASES the volume. I do see a 4558d IC op-amp in the circuit, perhaps it has the logic to "inverse" the ohm reading passed to it? (if this "theory" was correct, I would now never be able to run the amp at full volume?)
Hope someone can help me understand what should be a basic concept.